Answer:
12.2 or 12 2/9
Step-by-step explanation:
You set them equal to each other and solve
Answer:
The answer would be c2 + c + 6
Answer:
y=-2/5x+21/5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-5)/(3-(-2))
m=-2/(3+2)
m=-2/5
y-y1=m(x-x1)
y-5=-2/5(x-(-2))
y-5=-2/5(x+2)
y=-2/5x-4/5+5
y=-2/5x-4/5+25/5
y=-2/5x+21/5
He would pay about a $47.04 in total because 15% of $40.9 is about $6.14
We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
