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3 years ago

Which parent functions go through the origin? Select all that apply.

Mathematics

2 answers:

Vanyuwa [196]3 years ago

5 0

Answer:

A, C, D, E, F

Step-by-step explanation:

A parent cubic function goes through the origin because its parent function y=x^3 means you can plug in (0,0) as 0=0^3.

A reciprocal function does not go through the origin because its parent function y=1/x does not allow (0,0) to be plugged in as you cannot divide by 0.

A parent quadratic function goes through the origin because its parent function y=x^2 means you can plug in (0,0) as 0=0^2

A parent absolute value function goes through the origin because its parent function y=|x| means you can plug in (0,0) as 0=|0|

A parent linear function goes through the origin because its parent function y=x means you can plug in (0,0) as 0=0

A parent cube root function goes through the origin because its parent function y=cbrt(x) means you can plug in (0,0) as 0=cbrt(0)

Dvinal [7]3 years ago

3 0

It also goes from linear too, I don’t know what else sorry

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What is the equation of this line? y = 2x y=12x y=−2x y=−12x

Anna [14]

Y=2X

Looking at the line you can see that it is moving up from left to right, making it positive. So -2X and -12X are incorrect.

Next we can find the slope by putting rise over run. Chose a point on the line, I’ll use (2,4).
On this point we rise to 4 and run over to 2.
So for rise over run we have 4/2 which is 2.
So y=2x is correct.

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3 years ago

A cone has a diameter of 30 in. and a slant height of 17 in. What is the approximate volume of the cone?

Alex777 [14]

We need to find the height of the cylinder
pythagorean theorem
15 is the bottom leg (30/2=15)
17 is hypotonuse
b=height
15^2+b^2=17^2
225+b^2=289
minus 225 both sides
b^2=64
sqrt both sides b=8

Vcone=(1/3)hpir^2
d/2=r=30/2=15
h=8
V=(1/3)8pi15^2
V=(1/3)8pi225
V=8pi75
V=600pi
aprox pi=3.14159256
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round if nececary

7 0

3 years ago

Here is a easy one :) what is 100 divided -10?

hammer [34]

-10 is the answer... lol

8 0

3 years ago

Read 2 more answers

There are 15 girls and 10 boys in a 5th grade class. What is the ratio of girls to boys? Write this as a simplified fraction :

notsponge [240]

Step-by-step explanation:

15 + 10 = 25 people

15 are girls and 10 are boys and that makes 15/10 ratio.

15/10 divided by 5 each is 15/5=3 and 10/5=2 which gets you a simplified fraction of

3/2

Hope this helped!

7 0

3 years ago

Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.

larisa86 [58]

Answer:

a) $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

b) $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

c) $t_{\alpha/2}=-2.11$

d) $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is $\alpha=1-0.87=0.13$ and $\alpha/2 =0.065$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.065$ and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

Part b

On this case the confidence is 92% or 0.92 so the significance level is $\alpha=1-0.92=0.08$ and $\alpha/2 =0.04$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

$df=n-1=15-1=14$

We need values b,c on the t distribution with 14 degrees of freddom such that:

$P(t_{(14)}$ or $P(t_{(14)}>c)=0.04$ and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

Part c

The significance level is $\alpha=0.025$ and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

We need a value c on the t distribution with 17 degrees of freddom such that:

$P(t_{(17)}$ , and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values $t_{\alpha/2}=-2.11$

Part d

The significance level is $\alpha=0.08$ and $\alpha/2 =0.04$ . On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.04$ and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

6 0

3 years ago