Answer:
![x](https://tex.z-dn.net/?f=x)
Step-by-step explanation:
![x + 5 - 5 = x](https://tex.z-dn.net/?f=x%20%2B%205%20-%205%20%3D%20x)
Answer:
The bearing of B from A is 335 Degrees
Step-by-step explanation:
Measure bearings clockwise.
Bearings are measured from the North line.
There are 25 degrees between B and North.
360 Degrees in a circle.
360 - 25 = 335
a) The motion described by the particle is undoubtedly a uniformly accelerated rectilinear motion, since the trajectory is rectilinear and the acceleration is constant.
b) In order to calculate the acceleration, we must apply the formula mentioned above, in such a way that the acceleration gives us:
![\boldsymbol{a=\dfrac{v-v_{o}}{t-t_{o} }=\dfrac{25-5}{10-0 }=\dfrac{20}{10}=2 \ m/s^2 }](https://tex.z-dn.net/?f=%5Cboldsymbol%7Ba%3D%5Cdfrac%7Bv-v_%7Bo%7D%7D%7Bt-t_%7Bo%7D%20%7D%3D%5Cdfrac%7B25-5%7D%7B10-0%20%7D%3D%5Cdfrac%7B20%7D%7B10%7D%3D2%20%5C%20m%2Fs%5E2%20%20%20%20%7D)
Our acceleration is 2 meters per second squared.
c) We are asked to calculate the function of velocity in relation to time, we simply substitute in the formula.
![\boldsymbol{v=v0+at }\\\boldsymbol{v=2+5t }](https://tex.z-dn.net/?f=%5Cboldsymbol%7Bv%3Dv0%2Bat%20%7D%5C%5C%5Cboldsymbol%7Bv%3D2%2B5t%20%7D)
Very easy!!.
d) To know what speed the particle will have at the instant of t = 8s, it is enough to substitute the value of “t” in the previous formula.
![\boldsymbol{v=5+2(8)=5+16=21 \ m/s }](https://tex.z-dn.net/?f=%5Cboldsymbol%7Bv%3D5%2B2%288%29%3D5%2B16%3D21%20%5C%20m%2Fs%20%7D)
So the speed at time t = 8s is 21 m/s²
e) In this case we are asked to determine at what instant of time the particle will have a speed of 15 m/s, we replace this value in the formula, simply clearing the variable "t", that is:
![\boldsymbol{v=v_{0}+at }](https://tex.z-dn.net/?f=%5Cboldsymbol%7Bv%3Dv_%7B0%7D%2Bat%20%7D)
Clearing "t"
![\boldsymbol{t=\dfrac{v-v_{o}}{a} }](https://tex.z-dn.net/?f=%5Cboldsymbol%7Bt%3D%5Cdfrac%7Bv-v_%7Bo%7D%7D%7Ba%7D%20%20%7D)
Substituting the speed value
![\boldsymbol{t=\dfrac{v-v_{o}}{a}=\dfrac{15-5}{2}=\dfrac{10}{2}=5 \ seg }](https://tex.z-dn.net/?f=%5Cboldsymbol%7Bt%3D%5Cdfrac%7Bv-v_%7Bo%7D%7D%7Ba%7D%3D%5Cdfrac%7B15-5%7D%7B2%7D%3D%5Cdfrac%7B10%7D%7B2%7D%3D5%20%5C%20seg%20%20%20%20%7D)
That is to say that when the particle has a speed of 15 m/s, it will happen exactly at 5 seconds.
(70-23.9+69)/6=Answer
this is because you add them together and divide them by 6. dividing it makes it 1/6th
hope this helps!