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34kurt
3 years ago
11

Solve the following equation. 3x/7-2=15 (Must be a mixed number)

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

Mixed Number

39 \frac{2}{3}

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Answer:

;-;

There is no 30$ tokens

Step-by-step explanation:

i guess its A or b

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4 0
3 years ago
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X2 + 5x - 14 Select one of the factors of the quadratic expression.
vfiekz [6]
The equation factored would be (x+7)(x-2). As 7-2=5 and (7)(2)=14.
3 0
3 years ago
The average of 10 numbers is -5. A new number is added to the list making the average -6. What is the new number?
Shtirlitz [24]

Answer:

- 16

Step-by-step explanation:

Average is calculated as

average = \frac{total}{count}

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\frac{total}{10} = - 5 ( multiply both sides by 10 )

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let the number added be x, then

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total + x = - 66, that is

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x = - 16

The new number is - 16

4 0
3 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that  , \text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}

Then , for section A :

\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}

\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200

Similarly in Section B, \text{Sum of scores in sec B}=90\times20=1800

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz =\dfrac{\text{Total score}}{\text{Total students}}

=\dfrac{3000}{35}=85.7142857143\approx85.7

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0
2 years ago
The probability that a given urine sample analyzed in a pathology lab contains protein is 0.73 (event A). The probability that t
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The right answer for the question that is being asked and shown above is that: "e.Events A and B are dependent because P(A|B) = P(A)." The probability that a sample contains protein, given that albumin is detected, is 1. The statement that is true is this e<span>vents A and B are dependent because P(A|B) = P(A).</span>
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3 years ago
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