Answer:
=125
Step-by-step explanation:
5−7)(512)(5−2)
=
1
78125
(512)(5−2)
=
1
78125
(512)(5−2)
=(
1
78125
(244140625))(5−2)
=3125(5−2)
=3125(
1
25
)
=125
Answer:
The answer is D: only I and II
Step-by-step explanation:
I know for sure this is the correct answer. Hope this helped! Mark me Brainliest!
inequality could be used to find the number of models Walt builds which is Dwight builds at most 9 and Walt builds at most 4 .
<u>Step-by-step explanation:</u>
Here we have , Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most 9 models. We need to find Which inequality could be used to find the number of models Walt builds . Let's find out:
Let the the number Walt builds is x , So Dwight builds 7 fewer models than 4 times the number Walt builds i.e.
⇒ 
But , according to question Dwight builds at most 9 models i.e.
⇒
⇒ 
⇒ 
⇒ 
Therefore , inequality could be used to find the number of models Walt builds which is Dwight builds at most 9 and Walt builds at most 4 .
<span>f(x)=2x
f(1)=2*1=2
f^2(1)=2*2*1=4
f^3(1) =2*2*2*1=8
1. If you
continue this pattern, what do you expect would happen to the numbers as
the number of iterations grows?
I expect the numbers continue growing multiplying each time by 2.
Check your result by conducting at
least 10 iterations.
f^4(1) = f^3(1) * f(1) = 8*2 = 16
f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32
f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64
f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128
f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256
f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512
f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024
2. Repeat the process with an initial value of −1.
What happens as the number of iterations grows?
f(-1) = 2(-1) = - 2
f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4
f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8
f^4 (-1) = f^3 (-1) * f(-1) = - 8 * (-2) = 16
f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32
As you see the magnitude of the number increases, being multiplied by 2 each time, and the sign is aleternated, negative positive negative positive ...
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