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Step2247 [10]
3 years ago
6

What is the solution to the equation -4(2x+3) = 2x+6-(8x+2)?

Mathematics
1 answer:
aivan3 [116]3 years ago
8 0

Answer:

x = -8

Step-by-step explanation:

-4(2x+3) = 2x+6-(8x+2)

Distribute

-8x-12= 2x+6-8x-2

Combine like terms

-8x-12 = -6x+4

Add 8x to each side

-8x-12 +8x = -6x+4+8x

-12 = 2x+4

Subtract 4 from each side

-12-4 = 2x+4-4

-16 = 2x

Divide each side by 2

-16/2 = 2x/2

-8 =x

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Mashutka [201]

Answer:

r = 3.

Step-by-step explanation:

16 = 10 + √(3r + 27)

√(3r + 27) = 6

Square both sides:

3r + 27 = 36

3r = 36 - 27 = 9

r = 3.

Check the result:

Left side of the equation = 16

Right side = 10 + √(9 + 27)

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2 years ago
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528 - (528 \times .12) = answer
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3 years ago
Is 4(x+1) - 3 and 4x + 1 equivalent and why ??
Gala2k [10]

Answer:

Step-by-step explanation:

4x + 4 - 3

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Yes they both are equivalent because the algebraic expression is same

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Janaya buys a postcard from each travel destination she visits. Before starting her travels this year, Janaya had 20 postcards.
MrRa [10]

Answer:

The percentage increase in Jayana's postcard collection is 15%

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4 0
3 years ago
Write the equation of the circle with the given center and radius.
34kurt

Step-by-step explanation:

The standard equation of a circle is (x - h)^2 + (y - k)^2 = r^2

Center = (h, k)

#1

Center = (0,2)

h = 0

k = 2

r = 5

(x - h)^2 + (y - k)^2 = r^2

(x - 0)^2 + (y - 2)^2 = 5^2

#2

Center = (-4,-5)

h = -4

k = -5

r = \sqrt{2}

(x - h)^2 + (y - k)^2 = r^2

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#3

Center =(-1,3)

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k = 3

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#4

Center: (9,0)

h = 9

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(x - 9)^2 + (y - 0)^2 = \sqrt{3}^2

4 0
3 years ago
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