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stepladder [879]
3 years ago
7

Write the compound inequality that models the given situation. Tyler works at Chik-Fil-A and earns $7.50 per hour. His paycheck

from week to week is no less than $150 and no more than $225.
Mathematics
2 answers:
jasenka [17]3 years ago
6 0
Tyler works 20-30 hours a week.
mrs_skeptik [129]3 years ago
5 0
$150(greater than equal to)$7.5x(greater than equal to)$225
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I need help with this ​
yawa3891 [41]

Answer:

C

Step-by-step explanation:

In the graph given, we can expect the x axis to be horizontal and the y axis to be vertical. This means that the arm span represents y and the height represents x.

Therefore, if a girl on her team is 63 inches tall, we can say that y=x+2, and since height is x, y = 63 + 2 = 65

6 0
3 years ago
Please help answer ASAP Thanks will give BRAINLIEST and 15 points What is the volume of this prism?
serg [7]

Answer:

D) 672 in³

Step-by-step explanation:

The volume of a rectangular prism is found by the <em>product of its length, width, and height</em>, so the equation is<em> V = l * w * h</em>.

Plug in: <em>V = 12 * 7 * 8</em>

Multiply: V = 672 in³

4 0
3 years ago
Read 2 more answers
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
Help me with this question please!
BlackZzzverrR [31]

\large \rm  \frac{2 ^{3} }{  \sqrt[4]{2}  }

\large \rm  \frac{2 ^{3} }{2 ^{ \frac{1}{4} } }

  • Divide the terms with the same base by subtracting their exponents

\large \rm \: 2 ^{3 -  \frac{1}{4} }

  • Calculate the difference

\large \rm2 ^{ \frac{11}{4} }

7 0
2 years ago
What is the value of the fourth term in a geometric sequence for which a1= 30 and r = 1/2
Viktor [21]

Answer:

a_{4} = 3.75

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 30 and r = \frac{1}{2}, thus

a_{4} = 30(\frac{1}{2}) ^{3} = 30 × \frac{1}{8} = \frac{30}{8} = \frac{15}{4} = 3.75

4 0
3 years ago
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