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Hitman42 [59]
3 years ago
6

HELP me on this please

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

angle FEA is 100°

angle AEC is 20°

angle CEG is 60°

Step-by-step explanation:

angle AEC=angle DEB=20°

angle AEG=angle FED=80°

80°-20°=60°; angle CEG=60°

angle FEA+angle AEC+ angle CEG=180°

angle FEA=100°

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Y=x^2+bx+c;(-2,3)
Maksim231197 [3]
<h3>Answer:  b = 4 and c = 7.</h3>

===============================================

Explanation:

Comparing y = x^2+bx+c to y = ax^2+bx+c, we see that a = 1.

The vertex given is (-2,3). In general, the vertex is (h,k). So h = -2 and k = 3.

Plug those three values into the vertex form below

y = a(x-h)^2 + k

y = 1(x-(-2))^2 + 3

y = (x+2)^2 + 3

Then expand everything out and simplify

y = x^2+4x+4 + 3

y = x^2+4x+7

We see that b = 4 and c = 7.

8 0
2 years ago
a hot tub pump circulate 4 cubic feet of water per minute, how many cubic inches of water does it circulate earch minute?
Shtirlitz [24]

4 {ft  }^{3}  \times  {( \frac{12in}{ft} )}^{3}  = 6912 {in}^{3}

4 0
2 years ago
If x=5, evaluate x^5 * x^-3
Artyom0805 [142]

Answer: 25

Step-by-step explanation:

Plug in x to the expression.

5^5 * 5^{-3}\\

When there is the same base of exponents is being multiplied the exponents add together and the base stays the same.

So this simplifies to, 5^2.

This then solves to 25.

3 0
3 years ago
A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra
Ksivusya [100]
The Quadrilateral is JKLM, 

let M_{JK}, M_{KL}, M_{LM}, M_{JM}, be the midpoints of JK, KL, LM and JM respectively.

---------------------------------------------------------------------------------------------------------

Given any 2 point P(m,n) and Q(k,l),<span>

the coordinates of the midpoint of the line segment PQ are given by the formula:

M_{PQ}=( \frac{m+k}{2} ,&#10;\frac{n+l}{2}), </span>

-------------------------------------------------------------------------------------------------

thus the coordinates of points M_{JK}, M_{KL}, M_{LM}, M_{JM},

are as follows:

M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)


------------------------------------------------------------------------------------------------

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

 |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}&#10;}</span>

------------------------------------------------------------------------------------------------

thus the distances connecting the opposite entrances can be calculated as follows:


|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5

|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39


Thus the total distance of the paths joining the opposite entrances is 

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)


Answer: 104 m



8 0
3 years ago
Find the area of the following shape. You must show all work to receive credit
kirza4 [7]

Answer:

42 square units

Step-by-step explanation:

Draw segments - 5 to A, A to the point of intersection of Band C and from from the point of intersection of B, C upto 2. It will form a square with each side 8 units and four triangles.

Subtracting the area of 4 four triangles from the area of the square will give you the area of the required shape.

Area of the shape

=  {8}^{2}  -  \frac{1}{2}  \times 3 \times 6 - \frac{1}{2}  \times 5 \times 2 - \frac{1}{2}  \times 2 \times 3\\ - \frac{1}{2}  \times 2 \times 5 \\  \\  = 64 - 3 \times 3 - 5 \times 1  - 1\times 3 - 1 \times 5 \\  \\  = 64 - 9 - 5  - 3 - 5 \\  \\  = 64 - 22 \\  = 42 \:  {units}^{2}

3 0
3 years ago
Read 2 more answers
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