I believe the answer is A but im not sure , can someone check my answer?
2 answers:
You might be interested in
Answer:
<em>The probability that the second ball is red is 71%</em>
Step-by-step explanation:
<u>Probabilities</u>
We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).
The first ball can be red (R) or green (G). The probability that it's red is computed by
The probability is's green is computed by
If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is
If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is
The total probability of the second ball being red is
The probability that the second ball is red is 71%
Answer:
Step-by-step explanation:
1) In this question we've been given "a", the leading coefficient. and two roots:
2) There's a theorem, called the Irrational Theorem Root that states:
If one root is in this form then its conjugate
. is also a root of this polynomial.
Therefore
3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then: