Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
Answer:
(4x+7)(4x+7)
Step-by-step explanation:
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =

Area of large shaded circle =

Area of 4 small shaded circles =

Total area of shaded circles =

Shaded area as a fraction of that of the outer circle
:) Hope this answers your question :)
Answer:
g(f(0)) = 2
Step-by-step explanation:
To find g(f(0)), you must first find f(0).
f(x) = 3x + 1
f(0) = 3(0) + 1 = 0 + 1 = 1
Now you input 1 into function g(x).
g(x) = (4x + 2)/3
g(1) = [4(1) + 2]/3
g(1) = [4 + 2]/3
g(1) = 6/3
g(1) = 2
g(f(0)) = 2