Answer:
import java.util.Scanner;
public class Speed{
int speed;
public Speed(int speed){
this.speed = speed;
}
public void checkSpeed(){
if(speed >= 24 || speed <= 56){
System.out.println("Speed is normal");
}
else
System.out.println("Speed is abnormal");
}
public static void main(String...args){
Scanner input = new Scanner(System.in);
int userSpeed = 0;
System.out.println("Enter a speed: ");
userSpeed = input.nextInt();
Speed obj1 = new Speed(userSpeed)
obj1.checkSpeed();
}
Explanation:
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
public class MyClass {
public static void main(String args[]) {
int x = 1;
int total = 0;
for (int i = 1; i <= 10; i++){
x *= i;
total += x;
}
System.out.println(total);
}
}
This program finds the sum of that series to the tenth term, the sum is: 4037913. I hope this helps.
I believe the correct answer from the choices listed above is option C. It would be uncovering the genetic makeup of the eastern cottontail rabbit that will have a direct relation <span>to the science of ecology. Hope this answers the question. Have a nice day.</span>
