It’s 2 if you must 3x2 you will get 6 and 6 divide by 2 you get 3
The answer is everything except d, so A, B, and C
-80*-31 is actually -80×31
so the answer is 2480
hope this helps feel free to ask
Answer:
The expression used to find the change in temperature per hour is Algebraic expression
Thus per hour; the temperature falls at the rate of 
Step-by-step explanation:
A temperature falls from 0 to 
in 
Which expression finds the change in temperature per hour.
From the above given information;
The initial temperature is 0
The final temperature is
The change in temperature is 
Thus;
-12.25 ° = 3.5 hours
To find the change in x° per hour; we have;
x° = 1 hour
The expression used to find the change in temperature per hour is Algebraic expression
From above if we cross multiply ; we have;
(- 12.25° × 1 hour) = (x° × 3.5 hour)
Divide both sides by 3.5 hours; we have:
x° = - 3.5
x° = 
Thus per hour; the temperature falls at the rate of
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
