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AlekseyPX
3 years ago
5

Can I have some help I don't really understand this question.

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

40 square units

Step-by-step explanation:

This is a rhombus, so you multiply the two diagonals and divide by 2.

8x10÷2=40

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If –y + 2x^2 – x = -5y^3 then find dy / dx in terms of x and y.
vlada-n [284]

Answer:

dy/dx = \frac{4x-1}{1-15y^{2} }

Step-by-step explanation:

-y + 2x²- x = -5y³

2x² - x = y - 5y³

4x - 1 = dy/dx - 15y².dy/dx

dy/dx(1 - 15y²) = 4x - 1

dy/dx = \frac{4x-1}{1-15y^{2} }

8 0
3 years ago
PLEASE HELP I WILL MARK BRAINLIEST
Lelu [443]

Answer:

27 \:  {km}^{2}

Step-by-step explanation:

Given is the shape of a trapezoid.

Therefore,

Area of the trapezoid

=  \frac{1}{2} (2 + 7) \times 6 \\  \\  = 9 \times 3 \\  \\  = 27 \:  {km}^{2}

5 0
3 years ago
What is the length of the segment ĀB
solong [7]

Answer: 12

Step-by-step explanation: 7+5

8 0
3 years ago
your parents have 2744.69 on a credit card with a 12.75 apr they miss their minimum payment and there is a late fee of 29 how mu
Butoxors [25]

The balance at the beginning of the second month on the credit card, based on a 12.75% APR, is <u>$28,02.85.</u>

<h3>What is the APR?</h3>

The APR or annual percentage rate is the cost of finance charged to the borrower of a loan or a credit cardholder.

When the APR is divided by 12 months, it results in MPR, which can be used to determine the interest.

<h3>Data and Calculations:</h3>

Credit card balance at the beginning of the first month = $2,744.69

APR = 12.75%

Monthly APR = 1.0625% (12.75/12)

Late Fee = $29

Ending balance at the beginning of second month = <u>$28,02.85</u> ($2,744.69 x 1.010625% + $29)

Thus, the balance at the beginning of the second month on the credit card, based on a 12.75% APR, is <u>$28,02.85.</u>

Learn more about the APR at brainly.com/question/2772156

#SPJ1

4 0
2 years ago
Please help! it’s urgent
ycow [4]

Step-by-step explanation:

{9}^{ \frac{3}{2} }  \times  {27}^{ \frac{1}{2} }  =  {(3)}^{ \frac{3}{2} \times 2 }  \times  {(3)}^{ \frac{1}{2}  \times  3}  \\  =  {3}^{3}  \times  {3}^{ \frac{3}{2}  }  \\  =  {3}^{3 +  \frac{3}{2} }  \\  =  {3}^{4\frac{1}{2} }  \\  =  {3}^{ \frac{9}{2} }

8 0
3 years ago
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