Question

A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape. What is the probability that both grapes are red? about 39.7% about 41.5% about 42.5% about 44.5%

Answer 1

Answer:

About 41.5%

Step-by-step explanation:

Given:

A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.

To Find:

What is the probability that both grapes are red?

Answer choices:

about 39.7%

about 41.5%

about 42.5%

about 44.5%

Solution:

Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .

As the red grapes are 15..

Thus,

The probability of choosing a red grape the first time is 15/23.

Because out of the total 23 grapes only 15 were red grape.

The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice

Hence, the probability of choosing or eating two red grapes will be :

15/23×14/22

=105/253

=0.415

= 41.5%

Therefore, the probability that both grapes are red is about 41.5%

Kavinsky