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BaLLatris [955]
3 years ago
15

Find the y value at the point x = -2.​

Mathematics
2 answers:
Wewaii [24]3 years ago
5 0

By looking at the graph, we can visually determine that the value of y when point x = -2 is <u>-4.</u>

harina [27]3 years ago
5 0

Answer:

-4

Step-by-step explanation:

The y value at x=-2 is -4 because when you go to -2 on the x-axis the function is below there.  You can only go straight up or straight down to determine the y-value that corresponds to x=-2 so we go down because the function is below the x-axis there.

We are going to go down until we get on the graph of the line.  Scroll over with eyeballs to see that the y there is -4 (use the y-axis).

So the ordered pair (-2,-4) is on our line and when x=-2, y=-4.

Another example:

y=0 when x=2

Another example:

y=2 when x=4

Another example:

y=-3 when x=-1

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If g(x)=4x^2-16 were shifted 5 units to the right and 2 down hat would the new equation be
nadezda [96]

Answer:

This is the answer

Step-by-step explanation:

This is the solution, hope it helps

7 0
3 years ago
Anyone can u plsss help I now failing math and I need to get this right, I get to redo it so plsss anyone
vaieri [72.5K]

i think it is 487.5. i may be wrong tho. hope this helps!

3 0
3 years ago
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Compute the probability of flipping a coin once and getting heads, given that the previous flip was tails.
ra1l [238]

Answer:

the probability to flip a head is 50%

Step-by-step explanation:

I think.

5 0
3 years ago
Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
2 years ago
Someone plz help me I’ll mark as brainliest and 44 points
Harrizon [31]
I think it's the 2nd one.....p=24c
3 0
3 years ago
Read 2 more answers
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