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maksim [4K]
3 years ago
5

What is the anwser to 2y-4x=8

Mathematics
2 answers:
True [87]3 years ago
5 0
The answer is y=2x+8 because your original is y=my+b
Schach [20]3 years ago
5 0
Y=-2x+4 Since 4x does not contain the variable to solve for, move it to the right side of the equation by subtracting
4x from both sides.

Divide each term by
2

and simplify.
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Solve using substitution.
alexandr1967 [171]
You take the first equation and make a value for y. So 6x + y =7 change it to :
y = -6x + 7
Now in the second equation replace the “y” with -6x +7 this is what it means to use substitution method . Your combined equation will now be :
8x + 9(-6x + 7) =17
Now do distributive property and you get :
8x + -54x +63 =17
Now combine like terms ;
-46x +63 =17
-46x =-46
x = 1
Now replace 1 for X value and we can get the value of Y .
Y=1
X=1
8 0
3 years ago
I NEED HELP WITH THIS PLEASE
11Alexandr11 [23.1K]

Answer:

Perimeter = Side1 + Side2 + Side3

4x + 3y = 5x - 3y + x + 4y + Side3

4x + 3y = 6x + y + Side3

-2x + 2y = y + Side3

Step-by-step explanation:

I WISH IT COULD HELP

8 0
3 years ago
What is the focal length of the parabola with equation shown below?
GuDViN [60]
Patterns:  vertical : y = a(x - h)² + k          horizontal: x = a(y - k)² + h

Look at the patterns above and remember these key points.

<span>1) if the x is squared, the parabola is vertical. It either opens up or down. </span>
    if the y is squared, the parabola is horizontal. It either opens left or right.

2) if a is positive, the parabola opens up or to the right.
    if a is negative, the parabola opens down or to the left

<span>3) the vertex is at (h,k). Be very careful. locations of h and k varies if the parabola is vertical or horizontal. its sign is also different in those positions</span>
4 0
3 years ago
The length of a rectangle is 2cm less than 7 times the width. the perimeter is 60cm. find length
Bezzdna [24]

Answer:

26 cm

Step-by-step explanation:

we can make an equation to find the lengths

2(x+7x-2) = 60

x : length of width

7x-2 : the length of length

2 : the two pairs of length and width

solving this equation, we get x = 4

but that is not the answer

we have to plug in x=4 into 7x-2

7*4-2 = 28-2 = 26

4 0
3 years ago
Each of 100 students in the Allen School can only take 1 CSE class each, between the four classes CSE 311, CSE 312, CSE 331, and
Naddika [18.5K]

Answer:

P(a=31,b=39,c=7,d=23) = 0.000668

Step-by-step explanation:

Sample space, n = 100

Let the number of students signed up for CSE 311 = a

Let the number of students signed up for CSE 312 = b

Let the number of students signed up for CSE 331 = c

Let the number of students signed up for CSE 332 = d

Probability of taking CSE 311, P_a = 0.3

Probability of taking CSE 312, P_b = 0.4

Probability of taking CSE 331, P_c = 0.1

Probability of taking CSE 332, P_d = 0.2

P(a,b,c,d) = \frac{n!}{a! b! c! d!} p_a^{a}  p_b^{b}  p_c^{c}  p_d^{d} \\P(a=31,b=39,c=7,d=23) = \frac{100!}{31! 39! 7! 23!} *  0.3^{31} * 0.4^{39} * 0.1^{7}  0.2^{23}\\P(a=31,b=39,c=7,d=23) = \frac{4.58*10^{111}}{2.13*10^{56}* 5040 }* (1.57*10^{-55})\\P(a=31,b=39,c=7,d=23) = 0.000668

3 0
3 years ago
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