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3 years ago

What is the answer to 13-3n < -8

1 answer:

4 0

First you should subtract 13 from -8.
Then divide the answer by -3.
Because you are dividing by a negative number, reverse the sign and you will get your answer.

13 - 3n < -8
-8 - 13 = ?
-3n < ?
?/-3 = n

Like in this example,
3 - 5n < 13
13 - 3 = 10
-5n < 10
10/-5 = -2
n > -2

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PLE HELP ASAP WILL MARK BRAINLIEST IF YOU ARE CORRECT!!!!!!!!!

masya89 [10]

Answer:

(8, 6)=(x, y) | (6, 5)= (y, x)

Step-by-step explanation:

Start at the x, and find the value. Next, find the value of y.

You already know the value for y is 6, so next find the value of x, which is 5.

7 0

3 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

A vehicle purchased for $

Nataly [62]

Answer:

$10,870

Step-by-step explanation:

we can multiply the initial value (27500) by (1-.06), or 0.94, raised to the 15th power

27500(.94)^15 = 10,870.52

6 0

3 years ago

Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9

Tpy6a [65]

ANSWER

D.
$A=3,P=2\pi,PS=(4,9)$

EXPLANATION

The given function is

$f(x) = 3 \sin(x - 4) + 9$

Comparing to the general form of a trigonometric sine function,

$f(x) = A \sin(Bx-C)+D$

$A=3$
The amplitude is absolute value of A

$|A| = |3| = 3$

$B=1$

The period is given by

$p = \frac{2\pi}{ B}$

$p = \frac{2\pi}{ 1} = 2\pi$

$C=4$

is a shift to the right of 4 units.

and

$D=9$

is an upward shift of 9 units

Therefore the phase shift is (4,9).

The correct answer is D

6 0

3 years ago

Help me pls only 10points

NeX [460]

y=-7x+8

y=-7x-8

-7x+8=-7x-8

8=-8

x∈∅

B. No solutions

3 0

4 years ago