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OverLord2011 [107]
3 years ago
6

Can 10/5 be a whole number ?

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0
Yes,2 because i did it already and found out its 2
Rus_ich [418]3 years ago
3 0

Answer:

yes, 2

Step-by-step explanation:

10 over 5 is 2

2 is a whole number

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Which are measurements of the sides of a right triangle?
Radda [10]
It depends and the measurement of the angle.
30-60-90(shown in image)
or
45-45-90
Also, sometimes you can use Pythagorean theorem

3 0
3 years ago
(+6) + (-11) + (+5)+(-7)
tensa zangetsu [6.8K]

Answer:

(+6) + (-11) + (+5)+(-7)

(6) + (-11) + (5) - (7)

6 - 11 + 5 - 7

(6 + 5) + (-11 - 7)

11 - 18

= -7

3 0
2 years ago
Read 2 more answers
Where does the last one go???
Nostrana [21]

Answer:

is goes to ¨¨not a function¨¨

Step-by-step explanation:

8 0
3 years ago
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a
vlabodo [156]
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:

We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.

Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4

4 does not equal -8, therefore

The limit does not exist
4 0
2 years ago
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