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OverLord2011 [107]
4 years ago
6

Can 10/5 be a whole number ?

Mathematics
2 answers:
zavuch27 [327]4 years ago
7 0
Yes,2 because i did it already and found out its 2
Rus_ich [418]4 years ago
3 0

Answer:

yes, 2

Step-by-step explanation:

10 over 5 is 2

2 is a whole number

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HELP!!
Crazy boy [7]

Answer:

60

Step-by-step explanation:

45 divided by 9 is 5. So you multiply 4 times 5. Which equals 20. So 20 plus 45 is 65. Hope you understand it.

5 0
3 years ago
At the local bakery, Ariel bought 2 oatmeal cookies for $1.50. Mei bought 1/2 dozen oatmeal cookies for $4.50. Becky bought 8 oa
elena55 [62]

Answer: Yes. The cookies are $ .75 each. The total cost is proportional to the number of cookies purchased.

T = $.75 × c

Step-by-step explanation:

4 0
3 years ago
A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t
Licemer1 [7]
If A(t) is the amount of salt in the tank at time t, then the rate at which this amount changes over time is given by the ODE

A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}

A'(t)+\dfrac1{100}A(t)=15

We're told that the tank initially starts with no salt in the water, so A(0)=0.

Multiply both sides by an integrating factor, e^{t/100}:

e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}
\left(e^{t/100}A(t)\right)'=15e^{t/100}
e^{t/100}A(t)=1500e^{t/100}+C
A(t)=1500+Ce^{-t/100}

Since A(0)=0, we have

0=1500+C\implies C=-1500

so that the amount of salt in the tank over time is given by

A(t)=1500(1-e^{-t/100})

After 10 minutes, the amount of salt in the tank is

A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}
8 0
4 years ago
PLz help thank you<br> i will mark Brainliest<br> if right answer
Naddik [55]

Answer:

122

Step-by-step explanation:

for y 11*11 = 121

for x, it's just 1 since 1*1 = 1

and add 121+1

5 0
3 years ago
A container holds 50 electronic components, of which 10 are defective.
Gala2k [10]

Answer:

There is some inforrmation that is missing in this question. It should read:

A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

Answers

Part 1.   0.02

Part 2.  0.0375

Explanation

The probability is a chance of an event happening. It is calculated as;

probability = (Number of favourable outcome)/(Number of available outcome)

Part 1

6 are chosen at random. If 4 are not defective, then 2 are defective.

P(at least 4 are not defective) = 4/40 × 2/10

                                               = 1/10 ×1/5

                                               = 1/50

                                                = 0.02

Part 2

8 are chosen at random. If 3 are defective, the 5 are not defective.  

P(3 are defective) = 3/40 × 5/10  

                            = 15/400

                            = 3/80

                           = 0.0375

Step-by-step explanation:

4 0
3 years ago
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