If h(x) = f
le" class="latex-formula"> °

and
![h(x) = \sqrt[3]{x+3}](https://tex.z-dn.net/?f=h%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
, find

if
![f(x) = \sqrt[3]{x +2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%20%2B2%7D)
·
1 answer:
Answer:
g(x) = x+1
Step-by-step explanation:
f(x) = ![\sqrt[3]{x+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B2%7D)
h(x) =![\sqrt[3]{x+3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D)
h(x)= (fog)(x)= f(g(x))= ![\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
so
=![\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
cubing both sides ,we get
x+3 = g(x) +2
solving for g(x) ,we get
g(x) = x+1
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No 4.44 inot equal to 4.044
Answer:
90.8 m
Step-by-step explanation:
Pythagorean Theorem
A²+B²=C²
slant height = C
A = 19.6/2=9.8m
90.9 in to m = 2.3m
9.8²+B²=2.3²
B²=90.9²-2.3² = 8257.52
B=
= 90.8
The lcm of 1978 and 2832 is
2800848
This sounds a lot like an obtuse triangle. I hope this helps! :)