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IrinaK [193]
3 years ago
6

What's the the LCM of 1978 and 2832`

Mathematics
1 answer:
seropon [69]3 years ago
5 0
The lcm of 1978 and 2832 is 
2800848

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Rewrite the rarional exponent as a radical by extending the properties of integer exponents
Nataly_w [17]

Answer: C

Step-by-step explanation:

Simplify the expression to 2^1/4

Now transform the expression using a^m/n = n root a raised to a power of m.

And that's how you get your answer.

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3 years ago
Please help me on my problem! show me work (if you can, I mean not trying to sound rude)
faltersainse [42]
Divide 436.8 by 62.08


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4 years ago
Determine if the given value makes the equation true or false. For x3 – 8 = 15, if x = 69
MrRa [10]

Answer:

(69)(3)−8 = 15

199≠15

False

Step-by-step explanation:

hope it helps, 69(3) is already bigger than 15, then -8 makes it 199, which is definitely not equal to 15.

6 0
3 years ago
Read 2 more answers
Solve the inequality<br> -2≥4p+6+4
Alchen [17]

Hi there


-2 ≥ 4p + 6 + 4

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4p +10 ≤ -2

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4p/4 ≤ -12/4

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3 0
4 years ago
Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

5 0
3 years ago
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