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IrinaK [193]
3 years ago
6

What's the the LCM of 1978 and 2832`

Mathematics
1 answer:
seropon [69]3 years ago
5 0
The lcm of 1978 and 2832 is 
2800848

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4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are
Elina [12.6K]

Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.

Hypergeometric distribution:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • 1000 people means that N = 1000
  • 130 can wiggle their ears, thus k = 130
  • Two are selected, thus n = 2.

The probability that neither can wiggle his or her ears is P(X = 0), thus:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

5 0
2 years ago
Find the first six terms of the sequence. a1 = 1, an = 4 • an-1
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\bf \begin{array}{ccllll}&#10;n&term&value\\&#10;---&-----&-----\\&#10;1&a_1&1\\&#10;2&a_2&4\cdot a_{2-1}\\&#10;&&4\cdot a_1\\&#10;&&4\\&#10;3&a_3&4\cdot a_{3-1}\\&#10;&&4\cdot a_2\\&#10;&&16\\&#10;4&a_4&4\cdot a_{4-1}\\&#10;&&4\cdot a_3\\&#10;&&64\\&#10;5&a_5&4\cdot a_{5-1}\\&#10;&&4\cdot a_4\\&#10;&&256\\&#10;6&a_6&4\cdot a_{6-1}\\&#10;&&4\cdot a_5\\&#10;&&1024&#10;\end{array}
3 0
2 years ago
Somebody help.. im so lost!!
aleksley [76]
What type of math is this?
4 0
2 years ago
What is the value of x?
uranmaximum [27]

Answer:

x=\frac{160-51}{2} =54.5°

Step-by-step explanation:

"Theorem 9-13: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs."

Basically no matter what other circle, secant or tangent you get, you just use the formula Outer\angle=\frac{far.point - near.point}{2}

If you need the outer angle, just put the other angles in and solve

If you need the far or near point angle, re-arrange the formula to get that value.

6 0
2 years ago
I need help please and thank you​
Andrej [43]

Answer:

a=-7.275*967

Step-by-step explanation:

8 0
2 years ago
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