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4 years ago

Plese: 2+2.. My grandma doesn't believe me!

Mathematics

2 answers:

Hatshy [7]4 years ago

6 0

It is 4 i am not gonna lie

andrew-mc [135]4 years ago

4 0

Fish
You flip 1 two to face the other way, connect them and there you go
A more complicated answer would be 4 because 2 balls and 2 cubes would be 4 shapes in total

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Please help. i will mark you brainleist

djverab [1.8K]

Answer:

w = 1/8t

Step-by-step explanation:

So this is basically saying that for every 1 second that passed, 8 oz of water drip steadily into the bucket which can be expressed like this:

8w = t

Since t represents x and w represents y, we can simplify the equation by moving the 8 to the other side

w = 1/8t

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3 years ago

In how many places did the japanese troops land on december 8, 1941?

bezimeni [28]

The first battle in the Pacific between the empire of Japan against the US and its allies took place on December 8, 1941. The Japanese forces began their conquest on the pacific islands and it started its invasion of the Malaya. They were held by a resistance of British Indian fighter however it was not enough to hold off the overwhelming Japanese force.

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3 years ago

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I think its figure A but i am not sure.

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4 years ago

Read 2 more answers

Write an expression the "difference of eighteen and two"

Bess [88]

(D): 18-2

Aside from its actual definition—“difference” in math terms talks about and/or means to subtract. The difference is the result/answer to a subtraction problem.

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3 years ago

After once again losing a football game to the college'ss arch rival, the alumni association conducted a survey to see if alumni

antoniya [11.8K]

Answer:

a) The 90% confidence interval would be given (0.561;0.719).

b) $p_v =P(z>2.8)=1-P(z$

c) Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=64 represent were in favor of firing the coach

$\hat p=\frac{64}{100}=0.64$ estimated proportion for were in favor of firing the coach

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans for were in favor of firing the coach

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.64 - 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.561$

$0.64 + 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.719$

And the 90% confidence interval would be given (0.561;0.719).

Part b

We need to conduct a hypothesis in order to test the claim that the proportion exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.64=64>10$

$n(1-p_o)=100*(1-0.64)=36>10$

Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 100.

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=2.8$

The p value for the test would be:

$p_v =P(z>2.8)=1-P(z$

Part c

Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

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3 years ago