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Gemiola [76]
3 years ago
10

How many times can 2 go into 238​

Mathematics
1 answer:
Nataliya [291]3 years ago
5 0
Just divide 238/2
the answer is 119
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30 days were sunny out of 100 days. What fraction of the days were sunny? *
podryga [215]

Answer:

30/100

Step-by-step explanation:

Since it was 30 out of 100, the answer is 30/100.

4 0
3 years ago
Read 2 more answers
Adya and Ashley complete a work separately in 20 and 25 days respectively. After 10 days of their working together, they both le
Tom [10]

\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}

Number of days Adya took to complete the work = 20

Work done by Adya in 1 day = \frac{1}{20}

Number of days Ashley took to complete the work = 25

Work done by Ashley in 1 day = \frac{1}{25}

So,

Total work by Adya & Ashley in 1 day =

\frac{1}{20}  +  \frac{1}{20}  \\  =  \frac{5 + 4}{100}  \\  =  \frac{9}{100}

•°• Their total work in 10 days =

\frac{9 \times 10}{100}  \\  =  \frac{90}{100}  \\  =  \frac{9}{10}

Now,

The work left to be completed =

1 -  \frac{9}{10}  \\  =  \frac{10}{10}  -  \frac{9}{10}  \\  =  \frac{1}{10}

From this we know that,

Amber completes \frac{1}{10} of the work in 3 days.

So,

Time taken by Amber to complete the whole work =

3 \times 10 \\  = 30 \:  \: days

↦ If Amber alone would do the whole work, he would take \boxed{30 \ \ days} to complete it.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

4 0
3 years ago
/// WORTH 70 points /// ASAP ////
belka [17]

A community is developing plans for a pool and hot tub. The community plans to form a swim team, so the pool must be built to certain dimensions. Answer the questions to identify possible dimensions of the deck around the pool and hot tub.


Part I: The dimensions of the pool are to be 25 yards by 9 yards. The deck will be the same width on all sides of the pool. Including the deck, the total pool area has a length of (x + 25) yards, and a width of (x + 9) yards.

Write an equation representing the total area of the pool and the pool deck. Use y to represent the total area. Hint: The area of a rectangle is length times width. (1 point)

y = (x+25)(x+9)


Rewrite the area equation in standard form. Hint: Use the FOIL method. (1 point)


y = x^2 + 9x + 25x + 9(25)


y = x^2 +34x + 225


Rewrite the equation from Part b in vertex form by completing the square. Hint: Move the constant to the other side, add to each side, rewrite the right side as a perfect square trinomial, and finally, isolate y. (4 points: 1 point for each step in the hint)


y-225 = x^2 +34x


y-225 + 17^2 = x^2 +34x + 17^2


y-225 + 289 = (x+17)^2


y = (x+17)^2 - 64


What is the vertex of the parabola? What are the x- and y-intercepts? Hint: Use your answer from Part a to identify the x-intercepts. Use your answer from Part b to identify the y-intercept. Use your answer from Part c to identify the vertex. (4 points: 1 point for each coordinate point)

The vertex is where the squared term is zero, x=-17 , y =-64, (-17,-64)


The y intercept is y at x=0, so (0,225)


The x intercepts are the zeros; so at x=-25 and x=-9, aka (-25,0), (-9,0)


Graph the parabola. Use the key features of the graph that you identified in Part d. (3 points)


[Plot the points we generated and connect the dots. I'll leave the graphing to you]

In this problem, only positive values of x make sense. Why? (1 point)

<em>x</em> is the width of the pool edge; it must be positive.


What point on your graph shows a total area that includes the pool but not the pool deck? (1 point)


x=0, y=225 i.e. (0,225)



The community decided on a pool area that adds 6 yards of pool deck to both the length and the width of the pool. What is the total area of the pool and deck when x = 6 yards? (2 points)


(9+6)(25+6)=15(31)=465



Part II: A square hot tub will be placed in the center of an enclosed area near the pool. Each side of the hot tub measures 6 feet. It will be surrounded by x feet of deck on each side. The enclosed space is also square and has an area of 169 square feet. Find the width of the deck space around the hot tub, x.

Step 1: Write an equation for the area of the enclosed space in the form y = (side length)2. Hint: Don't forget to add x to each side of the hot tub. (1 point)



y=(x+6)(x+6)=(x+6)^2



Step 2: Substitute the area of the enclosed space for y in your equation. (1 point)


169 = (x+6)^2


Step 3: Solve your equation from Part b for x. (3 points)


x + 6 = \pm \sqrt{169}


x = -6&#10; \pm 13


x= 7 \quad \textrm{ or } \quad x= -19


Step 4: What is the width of the deck around the hot tub? Hint: One of the answers from Part c is not reasonable. (1 point)


Only the positive root works,


x=7 feet


5 0
4 years ago
Join the zoommmmmmmmmm
ddd [48]

Answer:

Ok

Step-by-step explanation:

5 0
3 years ago
The price of a movie ticket in a given year can be modeled by the regression equation y= 6.94(1.02^x) where y is the ticket pric
Harlamova29_29 [7]

Answer:

The answer is B) $10.31

Step-by-step explanation:


3 0
3 years ago
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