1.) C(t) = -0.30(t - 12)^2 + 40
for t = 12: C(12) = -0.30(12 - 12)^2 + 40 = -0.30(0)^2 + 40 = 40°C
For t = 24: C(24) = -0.30(24 - 12)^2 + 40 = -0.30(24 - 12)^2 + 40 = -0.30(12)^2 + 40 = -0.30(144) + 40 = -43.2 + 40 = -3.2°C
4.) F(t) = 9/5 C(t) + 32
for C(t) = 40°C: 9/5 (40) + 32 = 72 + 32 = 104°F
for C(t) = -3.2°C: 9/5(-3.2) + 32 = -5.76 + 32 = 26.24°F
5.) F(t) = 9/5 C(t) + 32 = 9/5 (-0.30(t - 12)^2 + 40) + 32 = -0.54(t - 12)^2 + 72 + 32 = -0.54(t - 12)^2 + 104
Answer:
The value 10 years is the population mean
Step-by-step explanation:
A sample consists of some observations drawn from the population, so a part or a subset of the population which in this case is the number of horses with colic.
A sample mean is the mean of the statistical samples while a population mean is the mean of the total population.
Thus, in this case, the sample mean is the mean age of the horses with colic while the population mean age is the mean age of all the horses found at the clinic.
Therefore, the mean age of 10 of the horses seen at the clinic would be the population mean.
5-7 = -2 and 1-6= -5 so the slope would be 2/5. you would set it up like this:
y=2/5x and then your y-intercept
Answer:
5/7
Step-by-step explanation:
Answer:
The third picture
Step-by-step explanation:
Solve for x in both equations
2x<6
Divide both sides by 2:
x<3
3x+2>-4
Subtract 2 from both sides:
3x>-6
Divide both sides by 3:
x>-2
There is this trick you can use when x is on the left side of the equation to find out which way to shade in you graph. Keep in mind this is only for the left side, it will not work if your variable is on the right.
When the symbol is facing left < then shade left, imagine it is pointing which way to shade. x<3 is represented by the 3 picture on the left. When the symbol is facing right > then shade right, again it is pointing which way to shade. x>-2 is represented by the 3 picture on the right.
The circles are not filled in because the symbol is < and > rather than 
. When it is greater than or equal to or less than and equal to (represented by the line under the symbol), then the circle is shaded in.
