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Korvikt [17]
3 years ago
9

What is the answer????

Mathematics
2 answers:
morpeh [17]3 years ago
7 0
2.5 cans of food ......
Nat2105 [25]3 years ago
5 0
1/2 cup of food total
You might be interested in
Use the quadratic formula to solve the equation if necessary round to the nearest hundredth x^2+x-30=0
yaroslaw [1]

Answer:

(x-5)(x+6)=0

Step-by-step explanation:

hehe i doing the smae unit rn.

if a=1 (which it does do ac factoring)

you need two numbers that multiply to -30 and add to 1. those numbers  are 5 and -6.

substitute 1x for -5x + 6x.

group the numbers into pairs and find their gcf's

x(x-5)    6(x-5)

since the parenthesis r the same yo only need one. Now you need to put x and 6 in a parenthesis.

FINAL: (x-5)(x+6) hope this helps

6 0
3 years ago
Geometry, help please ! :)
Dovator [93]

The bottom rectangle is 52 ft by 27 ft.

The top rectangle is 30 ft by 17 ft (calculated as 57 ft - 27 ft - 13 ft = 17 ft).

The connector rectangle is 13 ft by 9 ft (calculated as 30 ft - 21 ft = 9 ft).

total area = 52 ft * 27 ft + 30 ft * 17 ft + 13 ft * 9 ft

total area = 1404 ft^2 + 510 ft^2 + 117 ft^2

total area = 2031 ft^2

weight = 2031 ft^2 * 12 lb/ft^2

weight = 24,372 lb

4 0
3 years ago
A school has 63% percent girls and 37%, percent boys. If 23%, percent of the girls wears contacts and 42%, percent of the boys w
Degger [83]

Answer:

30% students

Step-by-step explanation:

Let x be the number of total students of a school.

63% are girls then total number of girls = (0.63)x

37% are boys then total number of boys = ( 0.37)x

Now 23% of girls wear contacts then total number of girls

= (0.63x) × 0.23

=  (0.1449x)

And 42% of boys wear contacts then total number of boys wearing contacts

= (0.37x) ( 0.42)

= (0.1554)x

Total students wears contacts = ( 0.1449x) + (0.1554x)

                                                  = (0.3003x)

Percentage of students wear contacts = \frac{\text{total students wear contacts}}{\text{total students in school}} × 100

= \frac{0.03003x}{x} × 100

= 30%

All 30% students wear contacts.

4 0
3 years ago
[Algebra 2] Find the quotient with the necessary restrictions.​
Tatiana [17]

Answer:

The correct answer is:   3x² (4x - 1) / (x - 4) (x - 3) ∧ restriction x ≠ 3, x ≠ 4, x ≠ 0 and x ≠ 1/4

Step-by-step explanation:

Given:

((16x² - 8x + 1) / (x² - 7x + 12)) : ((20x² - 5x) / 15x³) =

dividing with one fraction is the same as multiplying with its reciprocal value

((16x² - 8x + 1) / (x² - 7x + 12)) · (15x³ / (20x² - 5x))

First we need to factorize both numerators and denominators

16x² - 8x + 1 = (4x - 1)²   This is square binomial

x² - 7x + 12 = x² - 4x - 3x + 12 = x (x - 4) - 3 (x - 4) = (x - 4) ( x - 3)

20x² - 5x = 5x (4x - 1)

(4x - 1)² / (x - 4) (x - 3) ·  15x³ / 5x (4x - 1)

The existence of this rational algebraic expression is possible only if it is:

x - 4 ≠ 0 and x - 3 ≠ 0 and x ≠ 0 and 4x - 1 ≠ 0  =>

x ≠ 4 and x ≠ 3 and x ≠ 0 and x ≠ 1/4  This is restriction

Finally we have:

3 x² (4x - 1) / (x - 4) (x - 3)

God with you!!!

8 0
3 years ago
The length of a rectangle is 5 m less than twice the width, and the area is 33 m. Find the dimensions of the rectangle.
MrMuchimi
Check the picture below

it can't be -3... since is width unit, so it has to be the other

and recall that length = 2w - 5

7 0
3 years ago
Read 2 more answers
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