10x - y = 2<br> 5x + 3y = 5 --

Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th

soldier1979 [14.2K]

Answer:

$\frac{9}{20}$ students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

$\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}$

$\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}$

$\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}$

$\text{Students who play a sport and a part of the drama club}=\frac{9}{20}$

Therefore, $\frac{9}{20}$ students play sport and part of the drama club.

5 0

3 years ago

Rewrite each expression in the form kkxxnn, where kk is a real number and nn is an integer. Assume x ≠ 0.

labwork [276]

Answer:

The expression will be $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Step-by-step explanation:

We have given the expression $2x^5\times x^{10}$

We have to write this expression in kkxxnn form , here kk is real number and nn is integer

We know the property of exponent that when two function are multiplied thn their exponent are added

So $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Here kk = 2 and nn = 15

7 0

3 years ago

Determine the equation of the parabola shown in the diagram in factored form. (check picture below)

krok68 [10]

Answer:

$(x+1)(x-3)$

Step-by-step explanation:

A quadratic in factored form is usually expressed as: $a(x\pm a)(x \pm b)$ where the sign of a and b depends on the sign of the zero. And I said "usually" since sometimes the x will have a coefficient. Anyways in the quadratic there are two zeroes at x=-1 and x=3. This can be written as: $a(x+1)(x-3)$ . Notice how the signs are different? This is because when you plug in -1 as x you get a factor of (-1+1) which becomes 0 and it makes the entire thing zero since when you multiply by 0, you get 0. Same thing for the x-3 if you plug in x=3. Now a is in front and it can influence the stretch/compression. To find the value of a, you can take any point (except for the zeroes, because it will make the entire thing zero, and you can technically input anything in as a)