Alright, so in order to solve this, we need to isolate the variable. So, we need to simplify the equation. So, we have the equation:
82•P = 84
So, we need to divide both sides by 82 because it is the opposite of multiplication. So, we have :
82•P/82 = 84/82
So, 82•P/82 = 1p = P.
84/82 = P
If You Need Decimal Form,
84/82 = About 1.02
There are 64 ounces total in a half gallon
The height of the building to the nearest tenth of a meter is; 13 m
<h3>How to make use of Cosine Rule?</h3>
The slant line from the top of Trevor's head to the base of the building is gotten from Pythagoras theorem;
15/x = sin 36°
x = 15/sin 36
x = 25.52 m
Angle between that slant line and base of building is;
90 - tan⁻¹(1.5/14) = θ
θ = 83.88°
Remaining angle of the bigger triangle is;
180 - (36 + 83.88) = 60.12°
Thus, if the height of the building is h, then;
h/sin 36 = 25.52/sin 60.12
h = 13 m
Read more about Cosine Rule at; brainly.com/question/4372174
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You can solve real-world and mathematical problems with numerical and algebraic equations and inequalities. Algebra can be applied to the temperature in different places that both change, height of a growing child over time, the speed of a car that changes over time (mph), and the age of people that increases over year. Algebra is used in parts of our everyday life, we just don’t realize it.
4.) The lateral area of a figure is the area of the figure with the exception of the bases.
Given a prism with right triangle bases, the lateral area of the prism is the sum of the areas of the rectangles making up the prism.
This is given by
Lateral area = (8.94)(41) + (4)(41) + (8)(41) = 366.54 + 164 + 328 = 858.54 ≈ 859 m^2
The surface area is the sum of the bases plus the lateral area. The area of a rectangle is given by half base times height.
Surface area = 1/2 x 8 x 4 + 1/2 x 8 x 4 + 859 = 16 + 16 + 859 = 891 m^2
5.) The surface area of a cylinder is given by pi r^2h where r is the radius = 12 inches and h is the height = 17 inches.
Surface area = π x (12)^2 x 17 = 2,448π = 7,690.62 in^2 ≈ 7,691 in^2
