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3 years ago

14

GEOMETRY! Show your work, please.

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

54°

Step-by-step explanation:

$m\angle CDE = \frac{1}{2} \{237 \degree - (360 \degree -237 \degree ) \} \\ \\ = \frac{1}{2} \times \{237 \degree - 123 \degree \} \\ \\ = \frac{1}{2} \times 114 \degree \\ \\ = 54 \degree \\ \\ \huge \red{ \boxed{ \therefore \: m\angle CDE =54 \degree}}$

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Reika [66]

My bad if I read it wrong but I got 4.17

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4 years ago

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How many boys are there in an introductory chinese course if 363 students are enrolled and there are six boys to every five girl

loris [4]

There are 198 boys in the introductory Chinese course

<h3>How to determine the number of boys?</h3>

The given parameters are

Total = 363

Ratio = Boys : Girls = 6 : 5

So, we have

Boys =6/(5 + 6) * total number of students

This gives

Boys = 6/11 * 363

Evaluate

Boys = 198

Hence, there are 198 boys in the introductory Chinese course

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2 years ago

Kelly flies a distance of 2,100 miles. The trip takes 4 hours.

AnnyKZ [126]

Answer:

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B: In 13 hours the plane will travel 6,825 miles.

Step-by-step explanation:

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3 years ago

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Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of α

8_murik_8 [283]

Answer:

The value of angle α is 18 degree.

Step-by-step explanation:

Given information: Angles α and β are the two acute angles , α < β.

Given equation is

$\sin (2x-8)=\cos (6x-6)$

$\cos (90-(2x-8))=\cos (6x-6)$ $[\because \sin (90-x)=\cos x]$

Equating both sides.

$90-2x+8=6x-6$

$98+6=6x+2x$

$104=8x$

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The value of x is 13.

The measure of angles is

$2x-8=2(13)-8=18$

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Since 18<72, therefore the value of angle α is 18 degree.

8 0

4 years ago

I need help understanding this ASAP plz, I have a quiz over this next week!!!!

scZoUnD [109]

Answer:

Step-by-step explanation:

With any two points, you can find the line between them with:

$y = mx + b\\where\\m = \frac{y_2-y_1}{x_2-x_1}$

#1:

(-1, 1) -> (1, 3) $m = \frac{3-1}{1-(-1)} = 1, 3 = 1(1) + b, b = 2, y = x + 2$

(3, 4) -> (0, 2) $m = \frac{4-2}{3-0} = \frac{2}{3}, 2 = \frac{2}{3}(0) + b, y = \frac{2}{3}(x)+2$

(0, 1) -> (3, 3) $m = \frac{3-1}{3-0} = \frac{2}{3}, 1 = 2/3(0) + b, y = \frac{2}{3}(x) + 1$

Lines b and c are parallel because they have the same slopes

#2 is a bit easier

a: 2y = x + 12, $y = \frac{1}{2}(x) + 6$

b:2y - x = 5, $y = \frac{1}{2}(x) + \frac{5}{2}$

c: 2y + x = 4, $y = \frac{-1}{2}(x) + 2$

Since lines a and b have the same slope, they are parallel

#3:

(1, 3), y = 2x - 5

We have to find a line with a slope of 2 that passes through the two points

$y = 2x + b\\3 = 2(1) + b\\b = 1\\\\y = 2x + 1$

#4:

(-2, 1) , y = -4x + 3

We have to find a line with a slope of-4 that passes through the line

$y = -4x + b\\1 = -4(-2) + b\\1 = 8+ b\\b = -7\\y = -4x - 7$

#5:

(-2, 3) (1, -1), $m = \frac{3-(-1)}{-2-1} = \frac{-4}{3}, 3 = \frac{8}{3} + b, b = \frac{1}{3}, y = \frac{-4x}{3} + \frac{1}{3}$

(-3, 1) (1, 4), $m = \frac{4-1}{1-(-3)} =\frac{3}{4}, 4 = \frac{3(1)}{4} + b, y = \frac{3}{4}(x) + \frac{13}{4}$

(0, 2) (3, -2) $m = \frac{2-(-2)}{0-3} = \frac{-4}{3} , 2 = b, y = \frac{-4}{3}(x) + 2$

Since lines c and b have negative reciprocal slopes, they are perpendicular

#6:

a: y = -4x + 7

b: x = 4y + 2, $y = \frac{x}{4} - \frac{1}{2}$

c: -4y + x = 3, $y = \frac{x}{4} - \frac{3}{4}$

since lines a and c have negative reciprocal slopes, they are perpendicular

6 0

3 years ago