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kaheart [24]
3 years ago
9

Imagine that we mate two black labrador dogs with normal vision and find that three of the puppies are like the parents, but one

puppy is chocolate with normal vision and another is black with pra (progressive retinal atrophy, a serious disease of vision). we can conclude that the same alleles that control coat color can also cause pra. both of the parents are homozygous for both traits. the alleles for color and vision segregate independently during gamete formation. the alleles for color and vision segregate dependently during gamete formation. previous next
Biology
1 answer:
True [87]3 years ago
5 0
For the answer to the question above, I believe the answer based on the given information above, <span>the alleles for color and vision segregate independently during gamete formation. That's why the two Labradors are different. The other one is healthy and the other one is not. </span>
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Explanation:

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Use the key to identify each species. Write the letter of each species (A to G) in the correct
sveticcg [70]

Dichotomous keys are useful to identify organisms according to their morphological traits. The given key provides enough macroscopic morphological traits to identify these Arachnida species.

-----------------------------------------------

A dichotomous key is a significantly useful tool to classify organisms. The key provides an easy and fast way for identification by describing different morphological traits, leading you to the correct taxonomic classification.

The key provides morphological descriptions about different taxonomic groups in an easy way to identify these traits in your individual.

The term <em>dichotomous</em> refers to how information is provided. You will always have two options (a and b, or 1 and 2), and you will have to choose one of them according to the characteristics of your organism.  

In the exposed example, as the key provides morphological traits, we will separate the organisms<u><em> into two groups</em></u>:

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By recognizing each trait in each of the individuals, we will get to identify the species.

1

(a)  Abdomen <u>with a </u><u>tail</u> --------------------------- The only option is E

(b)  Abdomen <u>without a </u><u>tail</u><u> </u>----------------------  All the others A, B, C, D, F, G

2  ---<em>Only for  group A, B, C, D, F, G---</em>

(a) <u>Legs</u><u> much longer </u>than abdomen and  cephalothorax ----------A and G

(b)<u> </u><u>Legs</u><u> not much longer</u> than abdomen and  cephalothorax----- B, C, D, F

3  ---<em>Only for  group A, G---</em>

(a) <u>Hairs</u> on the legs -----------------------------------The only option is A

(b) <u>No hairs</u> on the legs ------------------------------ G

4  ---<em>Only for  group B, C, D, F---</em>

(a) Cephalothorax or <u>abdomen</u><u> segmented</u> ----------------The only option is D

(b) Cephalothorax or a<u>bdomen not segmented</u> ----------- B, C, F

5  ---<em>Only for  group  B, C, F---</em>

(a) Abdomen and cephalothorax <u>of the same size</u> --------The only option is F

(b) Abdomen and cephalothorax <u>of different size</u> -------B, C

6  ---<em>Only for  group B, C---</em>

(a) Body <u>covered with long</u><u> hair</u><u> </u>----------------------------------The only option is C

(b) Body<u> </u><u>not covered with</u><u> hair</u> ------------------------------------B

A  →  <em>Tegenaria domestica</em>

B  →  <em>Ixodes hexagonus</em>

C  →  <em>Tyroglyphus longior</em>

D  →  <em>Chelifer tuberculatus</em>

E  →  <em>Abaliella dicranotarsalis</em>

F  →   <em>Poecilotheria regalis</em>

G  →  <em>Odielus spinosus</em>

---------------------------------------------------

Related link: brainly.com/question/2235448?referrer=searchResults  

                    brainly.com/question/17365165?referrer=searchResults  

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