Answer:
3x-5
Step-by-step explanation:
Answer:
B. (-2, 3).........................
The discontinuity occurs when the denominator is equal to zero, as it has "infinite" slope, and thus is not a real value or point.
x^2+x-12
x^2+4x-3x-12
x(x+4)-3(x+4)
(x-3)(x+4)
So discontinuities occur when x=-4 and x=3
The roots are just the zero value of the formula. To find these, we factor:
(x - 2)(x - 2)
(x - 2)^2
to make this into a zero, we set x-2 = 0, then solve for x
x = 2
If x = 2, then the brackets = 0, and those are the roots
The roots are x = 2
Leave a comment if you couldn’t understand, and I’ll try to answer.
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