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Hitman42 [59]
3 years ago
8

Hi, i need help on these. thank you very much [urgent]

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

(4y - 3x) \times (4y + 3x)

( {11a}^{5}  -  {b}^{4} ) \times ( {11a}^{5}  +  {b}^{4} )

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0=x^2- 10x+10<br> Rewrite the equation by completing the square
zubka84 [21]

~~~~~~x^2 -10x +10  =0\\\\\implies x^2 -2 \cdot 5 \cdot x +5^2 -5^2 +10 = 0\\\\\implies (x-5)^2 -25+10 = 0\\\\\implies (x-5)^2 -15=0\\\\\implies (x-5)^2 =  15

4 0
2 years ago
What is the correct answer?
egoroff_w [7]
X⁴ - 81  = x⁴ - 9² (Difference of 2 squares, then we an write it:


(x²-3)(x²+3) =0, → then (x²-3) = 0 and (x²+3)=0

(x²-3) = 0 → x² = 3 → x = +√3 and x = -√3
(x²+3) =0 → x² = -3 → x = +√-3  and x = -√3→ or  i√3 AND  x = -i√3

A{ -3 , +3 , -i√3 , i√3}

4 0
3 years ago
/Which of the following is a solution of y - x &lt; -3? A= (6,2) B= (2,6) C= (2,-1)
konstantin123 [22]
C is the solution to the problem
3 0
3 years ago
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