<span>fast-moving particles colliding with slow-moving particles</span>
Tools we'll use:
-- Gravitational potential energy = (mass) x (gravity) x (height)
-- Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²
When the pendulum is at the top of its swing,
its potential energy is
(mass) x (gravity) x (height)
= (5 kg) x (9.8 m/s²) x (0.36 m)
= (5 x 9.8 x 0.36) joules
= 17.64 joules .
Energy is conserved ... it doesn't appear or disappear ...
so that number is exactly the kinetic energy the pendulum
has at the bottom of the swing, only now, it's kinetic energy:
17.64 joules = (1/2) x (mass) x (speed)²
17.64 joules = (1/2) x (5 kg) x (speed)²
Divide each side by 2.5 kg:
17.64 joules / 2.5 kg = speed²
Write out the units of joules:
17.64 kg-m²/s² / 2.5 kg = speed²
(17.64 / 2.5) (m²/s²) = speed²
7.056 m²/s² = speed²
Take the square root
of each side: Speed = √(7.056 m²/s²)
= 2.656 m/s .
Looking through the choices, we're overjoyed to see
that one if them is ' 2.7 m/s '. Surely that's IT !
_______________________________
Note:
The question asked for the pendulum's 'velocity', but our (my) calculation
only yielded the speed.
In order to describe a velocity, the direction of the motion must be known,
and the question doesn't give any information on exactly how the pendulum
is hanging, and how it's swinging.
We know that at the bottom of its swing, the motion is completely horizontal,
but we have no clue as to what direction. So all we can discuss is its speed.
Answer: a switch can do A, B and E
Explanation:
Answer:
0.125 A
Explanation:
From the question given above, the following data were obtained:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
The power in an electric circuit is given by the following equation:
Power (P) = current (I) × voltage (V)
With the above formula, we can obtain the rms current flowing through the bulb as shown below:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
P = Irms × Vrms
30 = Irms × 240
Divide both side by 240
Irms = 30 / 240
Irms = 0.125 A
Thus, the rms current flowing through the light bulb is 0.125 A
Answer: The light beam will not diffract out of the prism.
Explanation: The angle the light is entering the prism is greater than the critical angle therefore total internal reflection will occur. Hope this helps :)
