Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s
Explanation:
For proton, the centripetal force required for circular motion is provided by the magnetic force,
so Fm= Fc
q v B = m v²/r
m= mass of charged particle
v= velocity
B =magnetic field
q= charge
r= radius of circular path
v= q B r/m
now v= r ω
ω= angular velocity
ω r = q B r /m
ω=q B /m
now ω= 2π/T where T =time period
so 2π/T=q B/m
T= 2 πm/q B
T= 2π (1.67 x 10⁻²⁷)/ [( 1.6 x 10⁻¹⁹)* (0.9)]
T= 7.28 x 10⁻⁸ s
Easy. All you need to do us to is to shorten the number so that it only contains 3 digits. Change 2.9979248 to 2.99. Don't forget to round the number to the last possible digit. In this case, 2.997 would round to 3.00
So the answer would be 3.00x10^8.
Why?
Well, every non-0 number to the left of the decimal point will count as a significant figure. And every number to the right of the decimal point, whether it's 0 or not, will also count as a significant figure.
The 3 to the left of the decimal point and the 2 0s to the right will add up to 3 significant figures.
Answer:
The workdone by P is 
Explanation:
Generally workdone is mathematically represented as

Where F is the force and d is the distance
The total workdone = (Workdone by Force P + Workdone by frictional force )
The difference in kinetic energy

Substituting 5.6 J for
and 4.0 J for 

This change in kinetic energy of the block = The total kinetic energy
The workdone by the frictional force is

the negative sign shown that the force is moving in the opposite direction
substituting 1.2 N for
and 0.5 m for d


Making Workdone by Force P the subject in the above equation we
Workdone by Force P (
) = The total workdone(
) - 
Substitution values


Answer:
Wavelength of light will be 632.73 nm
Explanation:
We have given width of the single slit 
Angle is given as 
We have to find the wavelength of light for first dark fringe
We know that for dark fringe it is given that

For first fringe n = 1
So 
