Answer:
Solution given:
The volume of two similar solids are 128 m³
and 250 m³.
surface area of larger solid is 250m²
<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>
<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

x=128
the surface are of the
smaller solid is 128m²
Answer:
The correct answer is A: Interquartile range
Step-by-step explanation:
Just took the test and this was the correct answer
Answer:
1/2 , .5 , 50%
Step-by-step explanation:
Answer:
3(7a - 9)
Step-by-step explanation:
21a–27
3*7*a - 3*9
Factor out 3
3(7a - 9)