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masha68 [24]
3 years ago
15

A tennis ball travels at 120 miles per hour. what is this rate in feet per second

Mathematics
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:

176

Step-by-step explanation:

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Is 8 the HCF of 32, 48 and 72?
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Step 1

<u>Find the factors of each number</u>

we know that

32=2^{5} \\48=2^{4}*3\\72=2^{3}*3^{2}

Step 2

<u>Find the greatest common factor (GCF)</u>

the GCF is equal to----------> 2^{3}=8

therefore

<u>the answer is</u>

The GCF is 8

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3 years ago
Find the length of the midsegment.
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Answer:

50

Step-by-step explanation:

The length of the midsegment is half the length of the base segment, so you have ...

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Help PLEASE!!! Choices:<br><br> A.) $216<br><br> B.) $210<br><br> C.) $213<br><br> D.) $225
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Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
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