38.50 = 100%
31.57 = ?
Multiply: 31.57 x 100 = 3,157
Divide: 3,157 ÷ 38.50 = 82%
100-82= 18% discount
Answer:
A = 0.785m²
B = 31400cm²
C = 7850cm²
D = 785,000mm²
Step-by-step explanation:
To solve this question, we'll have to find the area of a circle which is
Area of a circle = πr²
1. The diameter of the circle = 1m
Area of a circle = πr²
r = radius of the circle
π = 3.14
Radius = diameter / 2
Radius = 1 / 2 = 0.5m
Area = 3.14 × (0.5)²
Area = 3.14 × 0.25
Area = 0.785m²
2. Radius = 100cm
Area of a circle = πr²
Area = 3.14 × (100)²
Area = 3.14 × 10000
Area = 31400cm²
3. Diameter = 100cm
Area = πr²
Radius = diameter / 2
Radius = 100 / 2
Radius = 50cm
Area = πr²
Area = 3.14 × (50)²
Area = 3.14 × 2500
Area = 7850cm²
4. Radius = 500mm
Area = πr²
Area = 3.14 × (500)²
Area = 3.14 × 250,000
Area = 785,000mm²
Answer:
The number of pounds of City Roast Columbian coffee they should buy is 1 and the number of pounds of French Roast Columbian coffee they should buy is 11.
Step-by-step explanation:
Let
x ----> the number of pounds of a City Roast Columbian coffee
y ---> the number of pounds of a French Roast Columbian coffee
we know that
-----> equation A
----> equation B
Solve the system of equations by graphing
The solution is the intersection point both graphs
The solution is the point (1,11)
therefore
The number of pounds of City Roast Columbian coffee they should buy is 1 and the number of pounds of French Roast Columbian coffee they should buy is 11.
Answer:
The statistical test to be used is the paired t-test.
Step-by-step explanation:
The dependent t-test (also known as the paired t-test or paired-samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference between these two means.
We use the paired t-test if we have two measurements on the same item, person or thing. We should also use this test if we have two items that are being measured with a unique condition.
For instance, an experimenter tests the effect of a medicine on a group of patients before and after giving the doses.
Similarly, in this case a paired t-test would be used to deter whether there was any changes in the cholesterol level within each group as result of the treatment.
Thus, the statistical test to be used is the paired t-test.
