Answer:
a line that might best estimate the data and be used for predicting values.
Choice B is correct
Step-by-step explanation:
A line of fit might be defined as;
a line that might best estimate the data and be used for predicting values.
This line connects most of the data points thus minimizing the squared residuals of the regression.
I hope this helps...
Perimeter of a closed figure is the sum of length of its outline. The perimeter of the consider triangular pool is:
units.
<h3>How to calculate perimeter of a triangular figure?</h3>
Perimeter of a triangle = Sum of lengths of all its 3 sides.
For the given case, we have:
Length of first side(hypotenuse) =
units
Height =
units
Base is of length 
Thus, its perimeter is calculated as:
Perimeter of a triangle = Sum of lengths of all its 3 sides.
Perimeter =
units
Perimeter =
units
Thus,
The perimeter of the consider triangular pool is:
units.
Learn more about perimeter here:
brainly.com/question/10466285
The equation that would let us determine the number of people or population at a certain year is calculated through the equation,
A(t) = A(o)(2^(t - 1950)/50)
Substituting the known values,
A(t) = (2.5 million people)(2^(2100 - 1950)/50))
A(t) = 20 million
<em>Answer: 20 million people</em>
The inverse of f does NOT exist. The reason why is because the function fails the horizontal line test. Recall that the horizontal line test is a test where you try to see if you can pass a single horizontal line through more than one point on the function curve. If you can get the horizontal line to pass through more than one point, then it fails the test. It's very similar to the vertical line test.
Answer:
C. x ≈ 0.28
Step-by-step explanation:
A graphing calculator solution is attached. It shows ...
x ≈ 0.28
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You can divide both sides of the given equation by 5, then take natural logs and divide by 5 again.
5e^(5x) = 20 . . . . . . given
e^(5x) = 4 . . . . . . . . divide by 5
5x = ln(4) . . . . . . . . take natural logs
x = ln(4)/5 . . . . . . . divide by 5
x ≈ 0.277259 ≈ 0.28