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3 years ago

Find the answer of (x⁴)-ᵌ is equal to

Mathematics

2 answers:

Alex787 [66]3 years ago

6 0

Answer:

$= {x}^{12} \\$

Step-by-step explanation:

$( {x}^{4} ) ^{ - 3} \\ {x}^{4 \times - 3} \\ = {x}^{12}$

hope this helps you

brainliest appreciated

good luck! have a nice day!

Eva8 [605]3 years ago

3 0

Answer:

x^-12

Step-by-step explanation:

(x^4)^-3 = x^ 4*-3 = x^-12

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8,508,400 divided by 10 to the sixth power

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3 years ago

The titanium content of an alloy is being studied in the hope of ultimately increasing the tensile strength. An analysis of six

HACTEHA [7]

Answer:

Tstatistic = - 3.068

Step-by-step explanation:

Given the data: 9.7% 7.4% 5.9% 7.7% 7.5% 8.9%

Mean titanium > 9.5%

Test statistic :

(m - μ) / (s/√n)

From the data: obtain the sample mean and standard deviation

From the data given ;

Calculate the same mean and standard deviation :

Using calculator :

Sample mean (m) = ΣX / n

Sample size (n) = 6

m = 47.1 / 6 = 7.85

Standard deviation (s) :

Using calculator = 1.317

Hence,

(m - μ) / (s/√n)

Tstatistic = (7.85 - 9.5) / (1.317/√6)

Tstatistic = - 1.65 / 0.5376629

Tstatistic = - 3.068

7 0

3 years ago

Can you tell me the definition of the highlighted word please in your own words (Thank you)

sattari [20]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Find the area of the shaded region in the graph y=x^2-2

Artist 52 [7]

By applying the concept of definite integral and the given restrictions, we conclude that the area of the shaded region in the graph is - 11/12.

<h3>How to find the area of the shaded region in the graph y = x² - 2</h3>

The area below the curve can be found by using definite integrals, which is defined here in this form:

$I = \int\limits^{1.5}_{0.5} {x^{2}-2} \, dx$ (1)

Now we proceed to calculate the area:

$I = \int\limits^{1.5}_{0.5} {x^{2}} \, dx - 2 \int\limits^{1.5}_{0.5}\, dx$

$I = \frac{x^{3}}{3}|_{0.5}^{1.5} - 2 \cdot x |_{0.5}^{1.5}$

$I = \frac{1.5^{3}-0.5^{3}}{3} - 2 \cdot (1.5 - 0.5)$

$I = -\frac{11}{12}$

By applying the concept of definite integral and the given restrictions, we conclude that the area of the shaded region in the graph is - 11/12.

<h3>Remark</h3>

The statement is incomplete. Complete form is shown below:

Find the area of the shaded region in the graph y = x² - 2, between x = 0.5 and x = 1.5

To learn more on definite integrals: brainly.com/question/14279102

#SPJ1

3 0

2 years ago

Let f(x) = 7x^2-5x+3 and g(x) = 2x^2+4x-6

Troyanec [42]

Answer:

$\large\boxed{A.\ f(x)+g(x)=9x^2-x-3}\\\boxed{B.\ f(x)-g(x)=5x^2-9x+9}\\\boxed{g(x)-f(x)=-5x^2+9x-9}$

Step-by-step explanation:

$f(x)=7x^2-5x+3,\ g(x)=2x^2+4x-6\\\\A:\\f(x)+g(x)=(7x^2-5x+3)+(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3+2x^2+4x-6\qquad\text{combine like terms}\\f(x)+g(x)=(7x^2+2x^2)+(-5x+4x)+(3-6)\\f(x)+g(x)=9x^2-x-3$

$B:\\f(x)-g(x)=(7x^2-5x+3)-(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3-2x^2-4x+6\qquad\text{combine like terms}\\f(x)-g(x)=(7x^2-2x^2)+(-5x-4x)+(3+6)\\f(x)+g(x)=5x^2-9x+9$

$C:\\g(x)-f(x)=(2x^2+4x-6)-(7x^2-5x+3)\\g(x)-f(x)=2x^2+4x-6-7x^2+5x-3\qquad\text{combine like terms}\\g(x)-f(x)=(2x^2-7x^2)+(4x+5x)+(-6-3)\\g(x)-f(x)=-5x^2+9x-9$

3 0

3 years ago