Question

If the point (-1/2, y) lies on the line whose equation is 2x - 3y = 6, what is the value of y?

Answer 1

Answer:

A. $-\frac{7}{3}$

Step-by-step explanation:

We have been given that the point $(-\frac{1}{2},y)$ lies on the line whose equation is $2x-3y=6$. We are asked to find the value of y.

To find the value of y, we will substitute $x=-\frac{1}{2}$ in our given equation as:

$2(-\frac{1}{2})-3y=6$

$-1-3y=6$

$-1+1-3y=6+1$

$-3y=7$

$\frac{-3y}{-3}=\frac{7}{-3}$

$y=-\frac{7}{3}$

Therefore, the value of y is $-\frac{7}{3}$

Answer 2

Hi

2x - 3y = 6
-3y = -2x + 6
y = -2x/-3 + 6/-3
y = 2x/3 - 2

For x=-1/2

y = 2(-1/2)/3 - 2
y = -1/3 - 2
y = (-1-6)/3
y = -7/3

2(-1/2) = -2/2 = -1
2(-1/2)/3 = -1/3

Answer: -7/3