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suter [353]
3 years ago
11

Which of the following statements is always true? a. Workers being paid on commission make less money than if they are salaried.

b. Workers being paid on commission have a salary that varies based on their performance. c. Workers being paid on commission are stressed over the amount of earnings they will have. d. Workers being paid on commission increase the accounting costs of the employer.
Mathematics
1 answer:
cricket20 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

The only answer that makes any sense is B. A commission works on the premise that the more you sell, the more money you take home.

Suppose a car salesman working at a GM dealership is working on a salary of 10% of the selling price. (A bit high).

Suppose on one month he sells 10 trucks, each one selling for 40000 dollars.

1 truck brings in 40000*10/100 = 4000 for the salesman.

10 trucks bring in 10*4000 = 40000 dollars.

The next month he only sells 8 Trucks. His commission is

40000 *  10/100 = 4000 per truck

8 trucks * 4000 = 32000 total for that month. A little less but it's quite a bit for a month's work all the same.

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Answer: 2 coins

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4 years ago
100 POINTS+BRAINLIEST: 8TH GRADE MATH PT 3- Write equations by simplifying polynomials Tyyy
d1i1m1o1n [39]

Answer:

d.  3x + 6 = 26

Step-by-step explanation:

<u>Definitions</u>

  • Integer:  a whole number that can be positive, negative or zero.
    e.g. ..., -3, -2, -1, 0, 1, 2, 3, ...
  • Even number: an integer that is exactly divisible by two.  For example, 2, 4, 6, 8 are all positive even numbers.
  • Consecutive: following one after the other in order.

<u>The sum of three consecutive even integers</u>

Let x be the first even integer.

As there is a <u>difference of 2</u> between <u>consecutive even integers</u>, the next even integer after x will be (x + 2).

Therefore, the next even integer after (x + 2) will be (x + 2) + 2 = (x + 4).

So "the sum of three consecutive even integers is twenty-six" is:

x + (x + 2) + (x + 4) = 26

<u>To solve</u>

⇒ x + (x + 2) + (x + 4) = 26

⇒ x + x + 2 + x + 4 = 26

⇒ 3x + 6 = 26

(Please note that there are no three consecutive even integers that sum to 26, so the problem cannot be solved).

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Step-by-step explanation:

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You roll 2 dice what is the probability that the sum of the dice is greater than 8 and that one die shows a six
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The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
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Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0
3 years ago
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