Let be be Beth, bi be Bill, and e be edie. Then:
1/be + 1/bi +1/e=1/12
1/bi + 1/e=1/15
10/be +10/bi +10/e+5/be+5/bi=1
Solve for be, bi, and e
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Hey there,
a-7=3(b+2), we do 3 times b and 3 times 2 according to the rule.
a-7=3b+6 we change + to - and - to + when move nums from 1 side to another one.
a=3b+13 we get the solution.
Hope this helps :)
