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3 years ago

6

Vertical angles are always congruent?

2 answers:

Alisiya [41]3 years ago

8 0

Yes. They will always be congruent.

Leviafan [203]3 years ago

5 0

Yes! Vertical angles are always congruent.

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Need help with this math please.

Cerrena [4.2K]

Answer:

Do what it says and i'll give you the answer.

Step-by-step explanation:

1. Because the slopes are negative recipricals of each other then these lines are perpendicular. y=x+7 (red line) y=-x+2 (green line) +graph%28+300%2C ...

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3 years ago

A trader bought a bag for one hundred and twenty five.he later sold it at a profit of Thirty percent what was his selling price

scZoUnD [109]

Answer:

I can’t really explain this bc i did it mentally, but i got 162.5

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3 years ago

A tower made of wooden blocks measures 114 feet high. Then a block is added that increases the height of the tower by 8 inches.

satela [25.4K]

Answer:

4. 23 in

Step-by-step explanation:

The tower is 1 1/4 feet high, then 8 inches are added. Well, we can't just add those two numbers. We have to change the units! Change everything to inches.

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<u>The answer is 4. 23 in. </u>

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4 years ago

The owner of a toy store received a shipment of 1,552 party favors. The party favors came in 28 boxes. The same number of party

Svetradugi [14.3K]

let

x = the number of party favors in each of the 27 boxes

y = the number of party favors in the last box

the total number of party favors is 1,552

27x + y = 1,552

since 1552 = 57*27 + 13

if we assume that y<x we conclude that there are 57 party favors in each of the 27 boxes and 13 party favors in the last box.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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3 years ago

A surveying team set up some equipment 104104 ft from the base of a tree in order to sight the top of the tree. From ground leve

jarptica [38.1K]

Answer:

Relative error = 0.0254 %

Step-by-step explanation:

Given details

Height of equipment from base is 104 ft

Elevation angle is 27.5 degree

From figure we have

$tan\theta = \frac{x}{104}$ .........1

$tan(27.5) = \frac{x}{104}$

x = 54.13 ft

differentiating 1st eq wrt x

$\frac{d}{dx} tan\theta = \frac{d}{dx} [\frac{x}{104}]$

$sec^2\theta \frac{d\theta}{dx} = \frac{1}{104}$

Taken $d\theta \ as \Delta x \ and\ dx = \Delta x$ for minute change

$\Delta x = 1.5% x$

$= 0.015 \times 54.13 = 0.8119 ft$

from $sec^2 \theta \frac{d\theta}{dx} = \frac{1}{104}$

$\Delta \theta = \frac{1}{104 sec^2 \theta} \Delta x$

$\Delta \theta = \frac{1}{104 \times 1.115} 0.8119$

$\Delta \theta = 0.007$

Reltaive error $= \frac{\Delta \theta}{\theta} \times 100$

$= \frac{0.007}{27.5}\times 100$

Relative error = 0.0254 %

4 0

3 years ago