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timurjin [86]
4 years ago
7

PLS HELP RN PLS I BEG YOU

Mathematics
2 answers:
ad-work [718]4 years ago
7 0

Answer:

185 bushes.

Step-by-step explanation:

500 x 0.37 = 185

Is this USA test prep?

Mandarinka [93]4 years ago
6 0

Answer: 185

Step-by-step explanation:

37% of 500 = 185

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Marlene only has enough ingredients to make a 1/4 batch of cookies. For the smaller batch, she only needs 2/3 cup of sugar. How
Art [367]

Answer:

A full batch of cookies will require \hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} \hspace{0.15cm} sugar,\hspace{0.15cm} or \hspace{0.15cm}2\hspace{0.15cm}whole\hspace{0.15cm} cups\hspace{0.15cm} and \hspace{0.15cm} \frac{2}{3} cup\hspace{0.15cm} of \hspace{0.15cm}sugar.

Step-by-step explanation:

i) \hspace{0.15cm}\frac{1}{4} batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm} \frac{2}{3} cup \hspace{0.15cm}of\hspace{0.15cm} sugar

ii) multiplying the above by 4 we get

\hspace{0.15cm}(4\times\frac{1}{4}) batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm}( 4 \times\frac{2}{3} )cup \hspace{0.15cm}of\hspace{0.15cm} sugar

iii) Therefore \hspace{0.15cm}1 batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} sugar

iv) Therefore a full batch of cookies will require \hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} \hspace{0.15cm} sugar,\hspace{0.15cm} or \hspace{0.15cm}2\hspace{0.15cm}whole\hspace{0.15cm} cups\hspace{0.15cm} and \hspace{0.15cm} \frac{2}{3} cup\hspace{0.15cm} of \hspace{0.15cm}sugar.

6 0
3 years ago
Help whit that 3 questions please and thanks
Serjik [45]

Answer:

80.

4s+5c=46\\3s+c=22

81. Each apple cost $0.50

82. One pound of chocolate = $3

Step-by-step explanation:

80.

Let sold of 1 senior citizen ticket be "s", and

cost of 1 child ticket be "c"

First Day, 4 senior citizen ticket and 5 child tickets sold, equaled $46, so the equation we can write is:

4s+5c=46

Second Day, 3 senior citizen ticket and 1 child ticket sold, equaled $22, so the equation we can write is:

3s+c=22

So, the system of equation (2 equations) written above can be solved simultaneously to find our answer.

4s+5c=46\\3s+c=22

81.

Let price of 1 apple be "a" and price of 1 banana be "b"

Since 3 apples and 2 banana cost $2, so we can write:

3a + 2b = 2

Then,

4 apples and 4 bananas cost $3, so we can write:

4a + 4b = 3

We can solve for the variable b in equation 1. Shown below:

3a + 2b = 2\\2b=2-3a\\b=\frac{2-3a}{2}

Now we put this value of b into equation 2 and solve for cost of 1 apple, a. Shown below:

4a+4b=3\\4a+4(\frac{2-3a}{2})=3\\4a+4-6a=3\\2a=1\\a=\frac{1}{2}\\a=0.5

So each apples cost $0.5

82.

Let 1 pound of chocolate be cost "c"

Let 1 pound of peanut be cost "p"

4 lb of chocolate and 2 lb of peanut = $16, thus we can write:

4c + 2p = 16

Next,

2 lb of chocolate and 3 lb of peanut costed $12, so we can write:

2c + 3p = 12

We solve first equation for p:

4c + 2p = 16\\2p=16-4c\\p=\frac{16-4c}{2}\\p=8-2c

Now, we put this expression for p into equation 2 and solve for c:

2c + 3p = 12\\2c + 3(8-2c) = 12\\2c+24-6c=12\\4c=12\\c=3

So, 1 pound of chocolates cost $3

5 0
4 years ago
Find the midpoint of the line segment with the given endpoint of (9,-1) , (0,7)
lapo4ka [179]

( \frac{9}{2}, 3 )

to calculate the midpoint use the midpoint formula

midpoint = [ \frac{1}{2}(9 + 0), \frac{1}{2}(- 1 + 7)] = (\frac{9}{2}, 3 )


5 0
4 years ago
A local lake has a fish population that follows a geometric series with these properties first time equals 48 ratio equals 1/4 d
kondaur [170]

Answer:

64.

Step-by-step explanation:

Sigma notation is ∑48(1/4)^(n-1).

Upper limit =   a1 / (1 - r)  where a1 = initial population and r = common ratio.

So it is 48 / (1 - 1/4)

= 48 / 3/4

= 48 * 4/3

= 64.

4 0
3 years ago
Suppose 29 cars start at a car race. In how many ways can the top 3 cars finish the​ race?
Ilia_Sergeevich [38]

any of the 34 cars can finish first  

any of the remaining 33 cars can finish second

any of the remaining 32 cars can finish third  

 

Thus, the top 3 finishes can be done in (34)(33)(32) = 35904 ways

8 0
4 years ago
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