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3 years ago

If 10 x equals 5 what is x

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

The answer for this question is gonna be .5 or 1/2

Leno4ka [110]3 years ago

4 0

Answer:

x= 0.5

Step-by-step explanation:

10x=5

First divide one side by 10 to isolate x, then divide 5 by 10

This makes x equal 0.5

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3 years ago

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Write an explicit formula for an, the nth term of the sequence 19,24,29

o-na [289]

Answer:

explicit formula for an, the nth term of the sequence 19,24,29

$a_1=19 ; \ a_n=a_{n-1}+5$

Step-by-step explanation:

We need to Write an explicit formula for an, the nth term of the sequence 19,24,29

In the sequence the First term a₁= 19

Common Difference d= 5

The Formula used for explicit formula is: $a_1=First \ term ; \ a_n=a_{n-1}+d$

Where d is common difference and n is nth term of sequence.

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3 years ago

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Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

Step-by-step explanation:

The question is incomplete:

What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions?

We can model this as a binomial random variable, with p=0.57 and n=14.

$P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}$

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

$P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\$

$P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\$

$P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\$

$P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886$

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Answer:

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