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Firlakuza [10]
3 years ago
12

How many covalent bonds does carbon form if each of its unpaired electrons participate in one bond?

Chemistry
1 answer:
yulyashka [42]3 years ago
8 0

Four covalent bonds.

<h3>Further explanation</h3>

Covalent (or homopolar) bonds occur based on the use or sharing of electron pairs. Covalent bonds are formed between nonmetallic elements.

We have the electronic configuration of a carbon atom as follows:  

\boxed{ \ _{6}C = 1s^2 \ 2s^2 \ 2p^2 \ or \ [He] \ 2s^2 \ 2p^2 \ }

  • The electronic configuration of carbon is \boxed{ \ 2,4 \ }
  • The electrons are distributed in the 1st and 2nd orbit.  
  • K shell (n = 1) = 2 electrons.
  • L shell (n = 2) = 4 electrons.

From this, we can see that the carbon atom has four unpaired electrons which are in the outer shell, called the valence electron.  

Carbon atoms with four electrons in the outer shell need four more electrons to reach a stable electron configuration such as a noble gas. Therefore, carbon atoms can form four covalent bonds with other non-metal atoms such as hydrogen, oxygen, nitrogen, sulfur, halogens, and even with carbon atoms themselves.

Recall that a carbon atom can form single, double, or triple bonds with other carbon atoms.

<h3>Learn more  </h3>
  1. Flammability as one of the chemical properties brainly.com/question/1767022
  2. About the single bonds in fatty acids brainly.com/question/1386856  
  3. The chemical formula for nitrobenzene brainly.com/question/2861241

Keywords: how many, covalent bonds, carbon, each of its unpaired electrons, participate in one bond, valence, outer shell, orbit, stable, the electronic configuration, non-metal atoms

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4.07 × 10⁹ mL

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Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

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Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

6.35ft \times \frac{1m}{3.28ft} = 1.94m

Step 3: Calculate the volume of water (V)

We will use the following expression.

V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}

Step 4: Convert "V" to mL

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Answer : The value of K_c of the reaction is 10.5 and the reaction is product favored.

Explanation : Given,

Moles of CH_3OH at equilibrium = 0.0406 mole

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First we have to calculate the concentration of CH_3OH,CO\text{ and }H_2 at equilibrium.

\text{Concentration of }CH_3OH=\frac{\text{Moles of }CH_3OH}{\text{Volume of solution}}=\frac{0.0406mole}{2.00L}=0.0203M

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\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.302mole}{2.00L}=0.151M

Now we have to calculate the value of equilibrium constant.

The balanced equilibrium reaction is,

CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)

The expression of equilibrium constant K_c for the reaction will be:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the values in this expression, we get :

K_c=\frac{(0.0203)}{(0.085)\times (0.151)^2}

K_c=10.5

Therefore, the value of K_c of the reaction is, 10.5

There are 3 conditions:

When K_{c}>1; the reaction is product favored.

When K_{c}; the reaction is reactant favored.

When K_{c}=1; the reaction is in equilibrium.

As the value of K_{c}>1. So, the reaction is product favored.

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