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Bad White [126]
3 years ago
15

A gene is a to a chromosome as

Chemistry
1 answer:
Fofino [41]3 years ago
8 0
I believe the answer would be A. A pea is to a pod
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Given that the molar mass of carbon is 12 g/mol and the molar mass of oxygen is 16 g/mol, calculate the molar mass of carbon dio
nekit [7.7K]
Molar mass of oxygen is:
M(O)=16 g/mol
Molar mass of carbon is:
M(C)=12 g/mol  
Molar mass of carbon dioxide is:
M(CO2)=M(C)+2*M(O)
 M(CO2)=12 g/mol+2*16g/mol
M(CO2)=44 g/mol

<span>Molar mass(M) is the mass of 1 mole of the substance (grams per mole of a compound).</span>
7 0
3 years ago
Which condition increases the number of collisions between reactant molecules in a given volume?
Nezavi [6.7K]

Answer:

Increasing Surface Area

Explanation:

A greater surface area (meaning more, smaller particles) allows for more opportunity for particles to collide.  On the other hand, decreasing temperature and removing a catalyst would only decrease the number of collisions, and the clumping option doesn't make much sense.  Hope this helps!

4 0
3 years ago
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WILL GIVE BRAINLIEST TO WHOEVER ACTUALLY GIVES RIGHT ANSWER. PLZ Which system of the human body allows oxygen to be dispersed to
IrinaK [193]

Answer:

circulatory system

Explanation:

it is what makes oxygen circulate

3 0
3 years ago
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WHO CAN HELP ME ON THIS NEED OF HELP! Due soon !
Otrada [13]

Answer:

Runoff from a cattle ranch

7 0
2 years ago
If 42 grams of carbon and 52 grams of oxygen are used, how many grams of CO2 will be produced (Hint: find the
zavuch27 [327]

Answer:

71.5g

Explanation:

The reaction equation is given as:

               C  +  O₂  →  CO₂

Mass of C = 42g

Mass of O₂  = 52g

Unknown:

Mass of CO₂ produced  = ?

Solution

Now to solve this problem, we have to find limiting reactant which is the one given in short supply in this reaction.

 The extent of the reaction is controlled by this reactant.

Find the number of moles of the given species;

 Number of moles  = \frac{mass}{molar mass}

      Number of moles of C  = \frac{42}{12}   = 3.5mol

     Number of moles of O₂   = \frac{52}{32}   = 1.63mol

Now;

   From the balanced reaction equation;

           1 mole of C reacted with 1 mole of O₂

We see that C is in excess and O₂ is the limiting reactant.

            1 mole of O₂ will produce 1 mole of CO₂

 So;      1.63mole of O₂ will produce 1.63 mole of CO₂

Mass of CO₂ = number of moles x molar mass

       Molar mass of CO₂ = 44g/mol

Mass of CO₂ = 1.63 x 44 = 71.5g

8 0
3 years ago
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