Answer:
As ΔABC is an <u>isosceles triangle</u>:
⇒ BA = BC
(the dashes on the line segments indicate they are of equal measure)
⇒ ∠BAC = ∠BCA = 55°
⇒ ∠BCA = ∠BAD = 55°
Angles on a <u>straight line</u> sum to 180°
⇒ ∠ADE + ∠EDC = 180°
⇒ 98° + ∠EDC = 180°
⇒ ∠EDC = 82°
As BE intersects AC, the <u>vertically opposite angles</u> are <em>equal</em>:
⇒ ∠BDC = ∠ADE = 98°
⇒ ∠ADB = ∠EDC = 82°
Interior angles in a triangle sum to 180°
⇒ ∠BAD + ∠ADB + ∠ABD = 180°
⇒ 55° + 82° + ∠ABD= 180°
⇒ ∠ABD = 180° - 55° - 82°
⇒ ∠ABD = 43°
Answer:
x=3
Step-by-step explanation:
cross multiply
5(x+3)=3(x+7)
5x+15=3x+21
5x+15-3x=3x+21-3x
2x+15=21
2x+15-15=21-15
2x=6
x=3
Answer:
3/5 or 0.6
Step-by-step explanation:
Here, given the value of tan theta , we want to find the value of sine theta
Mathematically;
tan theta = 0pposite/adjacent
Sine theta = opposite/hypotenuse
Firstly we need the length of the hypotenuse
This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.
Let’s call the hypotenuse h
h^2 = 3^2 + 4^2
h^2 = 9 + 16
h^2 = 25
h = √(25)
h = 5
Now from the tan theta, we know that the opposite is 3
Thus, the value of the sine theta = 3/5 or simply 0.6
Answer:
Height of a cell tower is, 30 m
Step-by-step explanation:
Proportion states that the two fractions or ratios are equal.
As per the given statement:
Let height of a cell tower be h.
Height of a pole = 3m ,
Shadow of a pole = 4 m and
shadow of a cell tower = 36+4 = 40 m
By definition of proportion;
Substitute the given values we get;
by cross multiply we get;
Divide both sides by 4 we get;
h = 30 m
Therefore, the height of a cell tower is, 30 m
