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Komok [63]
3 years ago
11

I don’t know how to solve the equation

Mathematics
1 answer:
Artemon [7]3 years ago
8 0
To solve this equation we have to factor.
We are looking for 2 numbers with a sum of -3, and multiplied they have to be -28. These numbers are -7 and 4.

So:
{x}^{2}  - 3x - 28 = 0
(x - 7)(x + 4) = 0
x - 7 = 0 \:  \:  \:  \: x + 4 = 0
x = 7 \:  \:  \:  \: x =  - 4

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tatyana61 [14]
Add $20 and $60 and your answer which is $80 dividdd that by 1.
5 0
3 years ago
What is the solution of the inequality shown<br> below?<br> y-1 &gt; 0
kipiarov [429]

Answer:

y>1

Step-by-step explanation:

y-1 > 0

Add 1 to each side

y-1 +1> 0+1

y>1

7 0
3 years ago
Please help me with this!!<br> Thank u
topjm [15]

Answer:

Step-by-step explanation:

Left

When a square = a linear, always expand the squared expression.

x^2 - 2x + 1 = 3x - 5                Subtract 3x from both sides

x^2 - 2x - 3x + 1 = -5

x^2 - 5x +1 = - 5                      Add 5 to both sides

x^2 - 5x + 1 + 5 = -5 + 5

x^2 - 5x + 6 = 0

This factors

(x - 2)(x - 3)

So one solution is x = 2 and the other is x = 3

Second from the Left

i = sqrt(-1)

i^2 = - 1

i^4 = (i^2)(i^2)

i^4 = - 1 * -1

i^4 = 1

16(i^4) - 8(i^2) + 4

16(1) - 8(-1) + 4

16 + 8 + 4

28

Second from the Right

This one is rather long. I'll get you the equations, you can solve for a and b. Maybe not as long as I think.

12 = 8a + b

<u>17 = 12a + b         Subtract</u>

-5 = - 4a

a = - 5/-4 = 1.25

12 = 8*1.25 + b

12 = 10 + b

b = 12 - 10

b = 2

Now they want a + b

a + b = 1.25 + 2 = 3.25

Right

One of the ways to do this is to take out the common factor. You could also expand the square and remove the brackets of (2x - 2). Both will give you the same answer. I think expansion might be easier for you to understand, but the common factor method is shorter.

(2x - 2)^2 = 4x^2 - 8x + 4

4x^2 - 8x + 4 - 2x + 2

4x^2 - 10x + 6    The problem is factoring since neither of the first two equations work.

(2x - 2)(2x - 3)     This is correct.

So the answer is D

5 0
3 years ago
If a quadratic equation has a discriminant that equals zero, which of the following statements is always true?
kotegsom [21]

Answer:

d. The equation has one solution and there is not enough information to determine the direction of the parabola.

Step-by-step explanation:

For a general quadratic equation

y = ax² +bx +c

the solution is

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The discriminant (D) is the part of the quadratic formula underneath the radical: b² - 4ac.

D tells us whether there are

  • two different real solutions
  • two identical real solutions ("one solution")
  • two complex solutions.

If D= 0,

x = \dfrac{-b}{2a}\pm0 = \mathbf{\dfrac{-b}{2a}}

and there are two identical solutions ("one solution").

The direction of the parabola depends on the sign of a.

That information is not given, so we cannot determine the direction of the parabola.

7 0
3 years ago
The table shows a function. Is the function linear or nonlinear?
Firdavs [7]

Answer:

nonlinear

Step-by-step explanation:

7 0
2 years ago
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