Answer:
55°
Step-by-step explanation:
Given that;
Lines CD and DE are tangent to circle A and intersect at point D.
and:
Arc CE measures 125 degrees. Point B lies on circle A.
There lies a diagrammatic representation below given a clear picture of what this question looks like;
If arc CE is 125°, what is the measure of ∠CDE?
SO, by using the outside angle theorem
∠CDE =
where arc CE = 125°
we can determine CBE by subtracting it from angle of a circle = 360°
Thus, CBE = 360° - 125°
CBE = 235°
Again; ∠CDE =
∠CDE =
∠CDE =
∠CDE = 55°
∴ The measure of ∠CDE = 55°
