You spin a spinner with 7 equal spaces numbered 1 through 7. What is the probability that the spinner lands
1 answer:
Answer:
<em>P = 28.57%</em>
Step-by-step explanation:
<u>Probability</u>
The probability of an outcome is defined as the frequency of the number of times the outcome occurs relative to the number of times that it could have occurred.
The equation to calculate the probability is:
Where f is the number of favorable cases and n is the total cases.
The spinner has n=7 equal spaces numbered 1 to 7. We will calculate the probability that the spinner lands on a 4 or a 6.
The set of favorable outcomes is {4,6} which gives a count of f=2.
The required probability is:
P = 28.57%
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Ok done. Thank to me :>
Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:
What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So
has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79