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Xelga [282]
4 years ago
5

What’s 0.308 rounded to the nearest hundredth?

Mathematics
2 answers:
elena-s [515]4 years ago
7 0
0.308 rounded to the nearest hundredth would be 0.31 .
Aleks04 [339]4 years ago
7 0

0.308 rounded to the nearest hundredth

For example , 0.549 can be rounded to 0.55

In 0.308, 3 is in tenths place, 0 is in hundredths place, 8 is in thousandths place. To rounded to the nearest hundredth,we look at the number in thousandths place.

Here 8 is in thousandths place. 8 is greater than 5 so we add 1 in hundredth place.

0.308 rounded to the nearest hundredth is 0.31


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Jenny and Chris share some prize money in the ratio 2:4. The prize money totaled $3000. How much did Chris win?
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2.4 percent *3000 =

(2.4:100)*3000 =

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Answer:

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SVETLANKA909090 [29]

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a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

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72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

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That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

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